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Top Forums Shell Programming and Scripting find command with wildcard directory Post 302533067 by srini0603 on Wednesday 22nd of June 2011 04:44:42 PM
Old 06-22-2011
Quote:
Originally Posted by Corona688
If you'd only said "dozens" I'd have have suggested this in the first place, but this is dangerous when you have lots of files and folders. There's a limit to how many things one glob can find -- in some shells, no more than a page or two worth.

The version with two finds has no limit at all.

You're only deleting some of the files. If they're not empty, I doubt you really want them deleted.

You'll need to use the two-find version to do this anyway, since it'd be torturous to get the right directory in one find and use it only once. I'll use 0-9, a-f if that worked for you.

Code:
# Find all directories in .../PROD-* beginning with [0-9a-f]
find /Production/ST/st*/Outbound/Prod/PROD-* -type d -name '[0-9a-f]*' -print -name '*' -prune
while read DIR
do
        # Find files in "${DIR}/PGP", delete them if old enough
        find "${DIR}/PGP" -type f -mtime +2 | xargs -d '\n' echo rm
 
        # Remove these directories only if they're empty
        rmdir "${DIR}/PGP" && rmdir "${DIR}"
# the rmdir's will cause some error messages when they fail, redirect that to /dev/null
done 2> /dev/null

find | xargs rm will run 'rm file1 file2 file3 ...' where find -exec rm would run 'rm file1; rm file2 ; rm file3 ...' so xargs makes it much faster. The -d '\n' is to tell xargs to consider anything but newlines as part of the filename.

The 'echo' is just a test, to print filenames instead of deleting as a test. Remove it once you're sure it's doing what you wanted.
can you tell me a bit more about two finds?

so in my case do I have to give it as 0-9,a-z as it could be anything between 0-9 and a-z as the first letter of the folder. is there any restriction on the # of directories I can search using this wildcard?

also won't the rmdir "${DIR}" delete the full structure? I just need only till the 32 char folder deleted and the rest should be intact.

P.S:
I just confirmed that it will be 32 chars and it will be consistent? so can i use the ??? approach? would that be better?
 

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lndir(1X)																 lndir(1X)

NAME
lndir - create a shadow directory of symbolic links to another directory tree SYNOPSIS
lndir fromdir [todir] DESCRIPTION
lndir makes a shadow copy todir of a directory tree fromdir, except that the shadow is not populated with real files but instead with sym- bolic links pointing at the real files in the fromdir directory tree. This is usually useful for maintaining source code for different machine architectures. You create a shadow directory containing links to the real source which you will have usually NFS mounted from a machine of a different architecture, and then recompile it. The object files will be in the shadow directory, while the source files in the shadow directory are just symlinks to the real files. This has the advantage that if you update the source, you need not propagate the change to the other architectures by hand, since all source in shadow directories are symlinks to the real thing: just cd to the shadow directory and recompile. The todir argument is optional and defaults to the current directory. The fromdir argument may be relative (e.g., ../src) and is relative to todir (not the current directory). Note that RCS, SCCS, and CVS.adm directories are not shadowed. Note also that if you add files, you must run lndir again. Deleting files is difficult because the symlinks will point to places that no longer exist. BUGS
The patch routine needs to be able to change the files. You should never run patch from a shadow directory. Use a command like the following to clear out all files before you can relink (if the fromdir has been moved, for instance): find todir -type l -print | xargs rm The following command will find all files that are not directories: find . ! -type d -print lndir(1X)
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