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Full Discussion: Merging all (48) CSV files from a directory
Top Forums Shell Programming and Scripting Merging all (48) CSV files from a directory Post 302532320 by Corona688 on Monday 20th of June 2011 03:20:10 PM
Old 06-20-2011
Not quite sure what you want with the file headers... Do you want all but the last ignored? All but the first? None of them ignored?

This can be adapted for any of those:
Code:
#!/bin/sh
cd /path/to/csvdir

(
        # set $1 = first file, $2 = second, etc.
        set -- *.csv

        # echo $1 $2 $3 ... $N changing space to comma with tr
        echo $* | tr ' ' ','

        # Print the first two lines (title) of first file
        head -n 2 $1

        # Loop through all files in $1, $2, ...
        for FILE
        do
                # Print out every file, ignoring first two lines
                tail "$FILE" -n +3
        done
# Dump the whole mess into the output file.  Don't put it in the
# same directory as the input files!
) > /path/to/output.csv

 

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MONGOEXPORT(1)							  Mongo Database						    MONGOEXPORT(1)

NAME

       mongoexport - the Mongo export tool

SYNOPSIS

       mongoexport [OPTIONS]

DESCRIPTION

       mongoexport  is a tool to export a MongoDB collection to either JSON or CSV. The query can be filtered or a list of fields to output can be
       given.

       If the output is CSV, the fields must be specified in order.

EXAMPLES

       mongoexport -d test -c test1 --csv -f name,num
	      export documents from test.test1 in CSV format

OPTIONS

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	      server to connect to (default HOST=localhost)

       -d, --db DATABASE
	      database to use

       -c, --c COLLECTION
	      collection to use

       -q, --query QUERY
	      query filter

       -f, --fields FIELDS
	      comma-separated list of field names

       --csv  export to CSV instead of JSON

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SEE ALSO

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AUTHOR

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