In C Shell programming I haven't successfully been able to append the date in the format mmddyyyy to a filename. I've tried the following:
I can print out the date in the correct format: date +%x | sed ‘s/\///g
I can create a variable with the filename: set newfile=changedfiles
I can... (3 Replies)
I need to extract the date part from the file name (20080221 in this ex) and compare it with the current date and delete it, if it is a past date.
$file = exp_ABCD4_T-2584780_upto_20080221.dmp.Z
really appreciate any help.
thanks
mkneni (4 Replies)
Hello,
I need to create a shell script that appends a filename to create a name with the date and time appended that is guaranteed to not exist. That is, the script insures you will not overwrite a file with the same name. I am lost with this one. I know I need to use date but after that I am... (3 Replies)
Hi,
There are similar kind of posts, but none seems like working for me. Please correct me if I'm wrong.
I need append/rename file abc.txt with file processed date and time like abc_systemdatetimestamp.txt
and move it to different folder.
for example I have
/source/data/abc.txt
... (1 Reply)
I have multiple txt files which begin with the word "orders" in folder C:\source. I need to move the files to folder C:\dest and rename them to "process_<date>_<count>"
So for example , if there are 3 files ordersa.txt , ordersb.txt and ordersc.txt in C:\source , after running the script I want... (1 Reply)
I have multiple txt files which begin with the word "orders" in folder C:\source. I need to move the files to folder C:\dest and rename them to "process_<date>_<count>"
So for example , if there are 3 files ordersa.txt , ordersb.txt and ordersc.txt in C:\source , after running the script I want... (7 Replies)
Hello,
I'd like to write a monthly archive script that archives some logs. But I'd like to do it based on yesterday's date. In other words, I'd like to schedule the script to run on the 1st day of each month, but have the archive filename include the previous month instead.
Here's what I... (5 Replies)
Suppose i have a list of files in a directory as mentioned below
1. Shankar_04152019_ny.txt
2. Gopi_shan_03122019_mi.txt
3. Siva_mourya_02242019_nd.txt
..
.
.
.
.
1000 . Jiva_surya_02282019_nd.txt
query : At one shot i want to modify the above all filenames present in one path with... (4 Replies)
Discussion started by: Shankar455
4 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)