#!/usr/bin/ksh
Does anyone have a good way to set a variable to last month?
For example, today is 20070810. I would like to use the date command to set a variable to last months %m code, which is 07. If I pluck this months value (08) and user expr to do simple math on it, it returns 7 (not... (5 Replies)
I want to get previous date from date command. I am using ksh shell.
Exmp:
today is 2008.09.04
I want the result : 2008.09.03
Please help.
Thanks in advance. (4 Replies)
Hi, I'm new with Unix, I'm trying to get a last day of previous month with this format: %b %d %Y (example: Feb 25 2008).
Here is what I have so far.
#!/bin/ksh
cur_month=`date +%m`
cur_year=`date +%Y`
prev_month=$(($cur_month-1))
# Check to see if this is January
if
then
... (11 Replies)
Hello,
I wanted to display the month for previous day date. Like, today date is 18-Nov-2008. So the previous date is 17-Nov-2008. The output should be November.
If the today date is 1-DEC-2008, then output should be NOVEMBER.
If the today date is 1-JAN-2008, then output should be DECEMBER.... (4 Replies)
Hello,
I'm new to shell scripting.
We've develop a script which will grep a file on the search criteria, MON (Jan/Feb/Mar/etc). But we should set this sript in cron which will run on every first day of the month. The problem I'm having is, when I run the script, it is displaying the contents of... (7 Replies)
Hi All,
I need to run a job every month at the beginning of the month which is scheduled through autosys, lets say on 03/01/2010. I need to pass the last month's i.e February's first_date = 02/01/2010 and last_date = 02/28/2010 as variables to a stored procedure. Can somebody please pass... (2 Replies)
Hi All,
I am using the below code to get the year and month from date:
Below gives output like 201212.
dt=`date '+%Y%m'`
how do i get the previous month value(ie: subtract 1 from date)
example output:
dt=201211
Please help. :confused: (3 Replies)
I have requirment to get last date of previous month and the first date of previous 4th month:
Example:
Current date: 20130320 (yyyymmdd)
Last date of previous month: 20130228 (yyyymmdd)
First date of previous 4th month: 20121101 (yyyymmdd)
In my shell --date, -d, -v switches are not... (3 Replies)
I am not able to fetch first date and last date previous month
date -d -1month +%Y-%m-%d
date -d -1month +%Y-%m-%d
I need two format dd-mm-yyy
previous month 01-03-2016
previous month 31-03-2016
and also only date 1 to 31
Aprriciate your replay (4 Replies)
Discussion started by: jagu
4 Replies
LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3)cal_from_jd - Converts from Julian Day Count to a supported calendarSYNOPSIS
array cal_from_jd (int $jd, int $calendar)
DESCRIPTION cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $jd
- Julian day as integer
o $calendar
- Calendar to convert to
RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and
the date in string form "month/day/year".
EXAMPLES
Example #1
cal_from_jd(3) example
<?php
$today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($today, CAL_GREGORIAN));
?>
The above example will output:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
SEE ALSO cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).
PHP Documentation Group CAL_FROM_JD(3)