Hi,
I want to know how to change this string to date format
20061102122042 to 02-11-2006 12:20:42
or 02-Nov-2006 12:20:42
Please let me know at the earliest.Thanks in advance.
Regards,
Preetham R. (3 Replies)
I know the command date +"%Y%m%d" can change today's date to digit format as below .
$date +"%Y%m%d"
20071217
it works fine .
now I want to do it back . If I have a file like below, (in the file , there are three lines, and each line have ; sign , after the ; sign is the date ) , I... (4 Replies)
Hi All,
this is my second post, last post reply was very helpful.
I have a data that has date in DD/MM/YYYY (07/11/2008) format i want to replace the backslash by a dot(.) so that my awk script can read it inside the C shell script that i have written.
i want to change 07/11/2008 to... (3 Replies)
Hi guys,
I have a text file with lots of lines like this:
MCOGT23R27815 27/07/07 27/05/09
SO733AM0235 30/11/07 30/11/10
NL123403N 04/03/08 04/03/11
0747AM7474 04/04/08 04/04/11
I want to change each line so the date format looks like this:
MCOGT23R27815 07/07/27 09/05/27 ... (7 Replies)
Dear Friends,
Need your help once again,
I have a variable ( e.g. ${i}) whoch has date in MM/DD/YYYY (E.g. 12/31/2011) format.
I want to change it to DD/MM/YYYY (e.g. 31/12/2011) format.
Request you to guide me as we are unable to do the same.
Thanks in advance
Anu. (1 Reply)
Hi,
I have the variable "$date_update" in that form:
2011-12-31T13:00:09Z and I would like to change it to
31/12/2011 13:00:09 (Date and Time separated by a blank).
Does anyone has a simple solution for that? (using Korn Shell)
Cheers
Jurgen (4 Replies)
Hi all,
I have a file that every line starts with the date and time. The format is like YYYYMMDDHHMM and I woulk like to change it to MM/DD/YY<space>HH:MM.
I tried to figure out a way to do it with sed, but I don't know how I could reorganize the digits of the first format. Does anyone have any... (1 Reply)
Hi,
I was looking for a script to change the date from one format to other. A search in the forum gave me the below script as a result.
#! /bin/ksh
format=YYYYMMDD
YEAR=${format%????}
DAY=${format#??????}
MON=${format#$YEAR}
MON=${MON%$DAY}
echo $MON/$DAY/$YEAR
I got it... (2 Replies)
Discussion started by: prithvirao17
2 Replies
LEARN ABOUT DEBIAN
software::release
Software::Release(3pm) User Contributed Perl Documentation Software::Release(3pm)NAME
Software::Release - Object representing a release of software.
VERSION
version 0.02
SYNOPSIS
use DateTime;
use Software::Release;
use Software::Release::Change;
my $change = Software::Release::Change->new(
author => 'gphat',
change_id => 'abc1234',
date => DateTime->now,
description => 'Frozzled the wozjob'
);
my $rel = Software::Release->new(
version => '0.1',
name => 'Angry Anteater',
date => DateTime->now,
);
$rel->add_to_changes($change);
DESCRIPTION
Software::Release is a purely informational collection of objects that you can use to represent a release of software. Its original use-
case was to provide a contract between a git log parser and a formatter class that outputs a changelog, but it may be useful to others to
create bug trackers, dashboards or whathaveyour.
ATTRIBUTES
changes
A list of Software::Release::Change objects for this release.
date
The date this software was released.
name
The name of this release.
version
The version of the release, as a string.
METHODS
add_to_changes ($change)
Add a change to this release's list of changes.
has_no_changes
Returns true if this release's list of changes is empty.
AUTHOR
Cory G Watson <gphat@cpan.org>
COPYRIGHT AND LICENSE
This software is copyright (c) 2011 by Infinity Interactive, Inc.
This is free software; you can redistribute it and/or modify it under the same terms as the Perl 5 programming language system itself.
perl v5.12.4 2011-10-19 Software::Release(3pm)