@Franklin52
You are right. Using 1 awk statement instead of 12 sed commands is much more efficient, but could you explain how this command works in this case. I'm sure its pretty simple, but it looks a little complex. Thanks
Code:
MTS=$(awk -v m=$MONTHEND 'BEGIN{printf( "%.2i\n",index(" JanFebMarAprMayJunJulAugSepOctNovDec", m )/3 )}')
The index() function returns the index of m (the given month) in the string of the 1st parameter.
The length of the month name is 3 and the index of the 1st month is 3, for the 2nd month 6 etc.
"Jan" gives 3; the month number is 3/3=1
"Feb" gives 6; the month number is 6/3=2
"Mar" gives 9; the month number is 9/3=3
"Apr" gives 12; the month number is 12/3=4
and so on..
Last edited by Franklin52; 06-14-2011 at 03:15 PM..
Reason: Typo
This User Gave Thanks to Franklin52 For This Post:
Hi,
Suppose I have the following text in a file.
ORA-00942: table or view does not exist
ORA-01555: snapshot too old: rollback segment number string with name "string"
too small
Is there any way I can list all the text that starts only with 'ORA-'?
Or there any grep command that can... (7 Replies)
Hi,
I have a file with rows of text like so :
E100005568374098100000015667
D100005568374032000000112682
H100005228374060800000002430
I need to grab just the last digits(bolded) of each line without the proceeding text/numbers.
Thanks (5 Replies)
Hi,
i am just gettin exposed to UNIX.
Could anyone of u help me out with dis problem..?
i have a variable 'act' which has the value as follows,
echo $act gives -0- -0- -----0---- 2008-06-04 -0- -0-
echo "$act" | awk '{print ($act)}'
gives,
-0-
-0-
-----0----
2008-06-04
-0-
-0-
I... (2 Replies)
i have a file that contains a pattern like this:
ajay 1234 newyork available
kumar 2345 denver
singh 2345 newyork
ajay 3456 denver
kumar 3456 newyork
singh 3456 delhi available
ajay 4567 miami
kumar 4567 miami
singh 4567 delhi
i want to search for each line... (5 Replies)
First of all I am VERY new to this so bare with me and try and explain everything even if it seems simple.
Basically I want to read a line of text from a html file. See if the line of text has a certain string in it. copy an unknown number of characters (the last 4 characters wiil be ".jpg" the... (1 Reply)
Hi,
I have a file in the following format
123|shanwer|15DEC2010|bgbh|okok|16JAN3000|okok|
I want the following to be in following format
123|shanwer|12\15\2010|bgbh|okok|01\16\3000|okok|
SED/PERL/AWK Gurus
could you please help me with this?
Thanks
Shankar (8 Replies)
Hi All,
Pls help me out on the below,
05 LAMSZ201-ZM-MEMO2-DATE02-5 PIC X(10).
05 LAMSZ201-ZM-MEMO2-AMT02-5 PIC S9(13)V99.
05 LAMSZ201-ZM-MEMO2-TYPE02-6 PIC XXX.
05 LAMSZ201-ZM-MEMO2-DATE02-6 PIC X(10).
05 ... (2 Replies)
Hello
Could you help with small script:
How to split string X1 into 3 string
String X1 can have 1 or many strings
X1='A1:B1:C1:D1:A2:B2:C2:D2:A3:B3:C3:D3'
This is output which I want to have:
Z1='A1:B1:C1:D1'
Z2='A2:B2:C2:D2'
Z3='A3:B3:C3:D3' (5 Replies)
i have something like this...
echo "teCertificateId" | awk -F'Id' '{ print $1 }' | awk -F'te' '{ print $2 }'
Certifica
the awk should remove 'te' only if it is present at the start of the string.. anywhere else it should ignore it.
expected output is
Certificate (7 Replies)
I'm making a little game in Perl, and I am trying to remove the first instance of a character in an arbitrary string. For example, if the string is
"cupcakes"and the user enters another string that contains letters from "cupcake" e.g:
"sake"the original string will now look like this (below)... (3 Replies)
Discussion started by: whyte_rhyno
3 Replies
LEARN ABOUT OSX
ncal
CAL(1) BSD General Commands Manual CAL(1)NAME
cal, ncal -- displays a calendar and the date of easter
SYNOPSIS
cal [-jy] [[month] year]
cal [-j] -m month [year]
ncal [-jJpwy] [-s country_code] [[month] year]
ncal [-Jeo] [year]
DESCRIPTION
The cal utility displays a simple calendar in traditional format and ncal offers an alternative layout, more options and the date of easter.
The new format is a little cramped but it makes a year fit on a 25x80 terminal. If arguments are not specified, the current month is dis-
played.
The options are as follows:
-J Display Julian Calendar, if combined with the -e option, display date of easter according to the Julian Calendar.
-e Display date of easter (for western churches).
-j Display Julian days (days one-based, numbered from January 1).
-m month
Display the specified month.
-o Display date of orthodox easter (Greek and Russian Orthodox Churches).
-p Print the country codes and switching days from Julian to Gregorian Calendar as they are assumed by ncal. The country code as deter-
mined from the local environment is marked with an asterisk.
-s country_code
Assume the switch from Julian to Gregorian Calendar at the date associated with the country_code. If not specified, ncal tries to
guess the switch date from the local environment or falls back to September 2, 1752. This was when Great Britain and her colonies
switched to the Gregorian Calendar.
-w Print the number of the week below each week column.
-y Display a calendar for the specified year.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month and year; the month is either a number between 1 and 12, or a full or abbreviated name as
specified by the current locale. Month and year default to those of the current system clock and time zone (so ``cal -m 8'' will display a
calendar for the month of August in the current year).
A year starts on Jan 1.
SEE ALSO calendar(3), strftime(3)HISTORY
A cal command appeared in Version 5 AT&T UNIX. The ncal command appeared in FreeBSD 2.2.6.
AUTHORS
The ncal command and manual were written by Wolfgang Helbig <helbig@FreeBSD.org>.
BUGS
The assignment of Julian--Gregorian switching dates to country codes is historically naive for many countries.
BSD November 23, 2004 BSD