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Top Forums Shell Programming and Scripting Need awk help to print specific columns with as string in a header Post 302525420 by arv_cds on Thursday 26th of May 2011 03:58:55 PM
Old 05-26-2011
Thanks. This works for the test file but not for the real file which has 4000 columns. and the substring "kkk" could be in any column and may be in 1000 different columns. Need an if statement in awk which can scan each header and find the header with string 'KKK' and then enter in print to select the column. Ask questions or put in your words to make sure that I am explaining it well.

Thanks, Again.
 

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SHTOOL-TABLE.TMP(1)					      GNU Portable Shell Tool					       SHTOOL-TABLE.TMP(1)

NAME
shtool-table - GNU shtool pretty-print a field-separated list SYNOPSIS
shtool table [-F|--field-sep sep] [-w|--width width] [-c|--columns cols] [-s|--strip strip] strsepstr... DESCRIPTION
This pretty-prints a list of strings as a table. OPTIONS
The following command line options are available. -F, --field-sep sep Separate columns using sep. Default is ":". -w, --width width Width of each column. Default is 15 characters. -c, --columns cols Number of columns. Default is 3. -s, --strip strip Strip off any characters past strip. Default is 79. EXAMPLE
# shell script shtool table -F , -w 5 -c 4 "1,2,3,4,5,6,7,8,9,10,11,12" HISTORY
The GNU shtool table command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1999 for GNU shtool. SEE ALSO
shtool(1), tr(1), fmt(1), sh(1), awk(1), sed(1). 18-Jul-2008 shtool 2.0.8 SHTOOL-TABLE.TMP(1)
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