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Full Discussion: How to calculate months and display in shell scripting
Top Forums Shell Programming and Scripting How to calculate months and display in shell scripting Post 302525308 by Tytalus on Thursday 26th of May 2011 10:31:06 AM
Old 05-26-2011
not sure exactly what you mean...do you want all months for a given year ? or all successive months, or just next month?

here's a start point for you to have a play with:

Code:
#  for x in {1..12}; do printf "20-%02d-2011\n" $x ;done
20-01-2011
20-02-2011
20-03-2011
20-04-2011
20-05-2011
20-06-2011
20-07-2011
20-08-2011
20-09-2011
20-10-2011
20-11-2011
20-12-2011

HTH
 

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LEARN ABOUT DEBIAN

index_dump

INDEX_DUMP(1p)						User Contributed Perl Documentation					    INDEX_DUMP(1p)

NAME

       index_dump - Show the content of the index file

FORMAT

	       index_dump [options] file [ tag ]

       where options are

	       --debug	       set debug level
	       --type	       specifies the num/date/char type of the index
	       --start	       defines the value to start dump from
	       --n	       prints also the total number of records
			       in the file

SYNOPSIS

	       index_dump rooms.cdx FACILITY
	       index_dump --debug=14 --start=Dub rooms.cdx ROOMNAME

DESCRIPTION

       Index_dump prints to standard output the content of the index file.  The type of the index is one of those supported by the XBase::Index
       Perl module (cdx, idx, ntx, ndx, mdx).

       The output contains the index key and the value, which is the record number in the correcponding dbf file.

       For mulitag index files (like cdx), you need to specify the tag name to get the actual data.

AVAILABLE FROM

       http://www.adelton.com/perl/DBD-XBase/

AUTHOR

       (c) 1999--2011 Jan Pazdziora.

SEE ALSO

       perl(1); XBase::Index(3pm); dbf_dump(1p)

perl v5.12.4							    2011-08-31							    INDEX_DUMP(1p)
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