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Top Forums Shell Programming and Scripting Retrieve logs generated in last 10 mins from a log file using 'grep' command Post 302525280 by 116@434 on Thursday 26th of May 2011 09:12:11 AM
Old 05-26-2011
well it's not a exact solution, but this one will print entries from file based on last time entry in the log. Hope this will work for you:

Code:
 
sed -n "/`cut -c1-16 m|uniq|tail -5|head -1`/,/`cut -c1-16 m|tail -1`/p" m

here m is the filename
 

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TAIL(1) 						      General Commands Manual							   TAIL(1)

NAME
tail - deliver the last part of a file SYNOPSIS
tail [ +-number[lbc][rf] ] [ file ] tail [ -fr ] [ -n nlines ] [ -c nbytes ] [ file ] DESCRIPTION
Tail copies the named file to the standard output beginning at a designated place. If no file is named, the standard input is copied. Copying begins at position +number measured from the beginning, or -number from the end of the input. Number is counted in lines, 1K blocks or bytes, according to the appended flag or Default is -10l (ten ell). The further flag causes tail to print lines from the end of the file in reverse order; (follow) causes tail, after printing to the end, to keep watch and print further data as it appears. The second syntax is that promulgated by POSIX, where the numbers rather than the options are signed. EXAMPLES
tail file Print the last 10 lines of a file. tail +0f file Print a file, and continue to watch data accumulate as it grows. sed 10q file Print the first 10 lines of a file. SOURCE
/src/cmd/tail.c BUGS
Tails relative to the end of the file are treasured up in a buffer, and thus are limited in length. According to custom, option +number counts lines from 1, and counts blocks and bytes from 0. Tail is ignorant of UTF. TAIL(1)
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