#!/usr/bin/perl
open I, "$ARGV[0]";
while (<I>){
chomp;
push @x, split / /, $_;
}
@x=sort {$a<=>$b} @x;
for ($i=0;$i<=$#x;$i+=($#x+1)/5){
printf "%d%s of numbers is bigger than %s\n", 100-$i/($#x+1)*100,"%",$x[$i];
}
How to replace many numbers with one number in a file.
Many numbers like 444565,454678,443298,etc. i want to replace these with one number (300).Please halp me out. (2 Replies)
I have two files one (numbers file)contains the numbers(approximately 30000) and the other file(record file) contains the records(approximately 40000)which may or may not contain the numbers from that file.
I want to seperate the records which has the field 1=(any of the number from numbers... (15 Replies)
Howdy experts,
We have some ranges of number which belongs to particual group as below.
GroupNo StartRange EndRange
Group0125 935300 935399
Group2006 935400 935476
937430 937459
Group0324 935477 935549
... (6 Replies)
Hi all,
I have a large column of numbers like
5.6789
2.4578
9.4678
13.5673
1.6589
.....
I am trying to make an awk code so that awk can easily go through the column and arrange the numbers from least to highest like
1.6589
2.4578
5.6789
.......
can anybody suggest, how can I do... (5 Replies)
Hi, I have a list.txt file with number ranges and want to print/save new all.txt file with all the numbers and between the numbers.
== list.txt ==
65936
65938
65942 && 65943
65945 ... (7 Replies)
Hi again. Sorry for all the questions — I've tried to do all this myself but I'm just not good enough yet, and the help I've received so far from bartus11 has been absolutely invaluable. Hopefully this will be the last bit of file manipulation I need to do.
I have a file which is formatted as... (4 Replies)
Hi!
I found and then adapt the code for my pipeline...
awk -F"," -vOFS="," '{printf "%0.2f %0.f\n",$2,$4}' xxx > yyy
I add -F"," -vOFS="," (for input and output as csv file) and I change the columns and the number of decimal...
It works but I have also some problems... here my columns
... (7 Replies)
Discussion started by: echo manolis
7 Replies
LEARN ABOUT DEBIAN
pperl
PPERL(1p) User Contributed Perl Documentation PPERL(1p)NAME
PPerl - Make perl scripts persistent in memory
SYNOPSIS
$ pperl foo.pl
DESCRIPTION
This program turns ordinary perl scripts into long running daemons, making subsequent executions extremely fast. It forks several processes
for each script, allowing many processes to call the script at once.
It works a lot like SpeedyCGI, but is written a little differently. I didn't use the SpeedyCGI codebase, because I couldn't get it to
compile, and needed something ASAP.
The easiest way to use this is to change your shebang line from:
#!/usr/bin/perl -w
To use pperl instead:
#!/usr/bin/pperl -w
WARNINGS
Like other persistent environments, this one has problems with things like BEGIN blocks, global variables, etc. So beware, and try checking
the mod_perl guide at http://perl.apache.org/guide/ for lots of information that applies to many persistent perl environments.
Parameters
$ pperl <perl params> -- <pperl params> scriptname <script params>
The perl params are sent to the perl binary the first time it is started up. See perlrun for details.
The pperl params control how pperl works. Try -h for an overview.
The script params are passed to the script on every invocation. The script also gets any current environment variables, the current working
directory, and everything on STDIN.
Killing
In order to kill a currently running PPerl process, use:
pperl -- -k <scriptname>
You need to make sure the path to the script is the same as when it was invoked.
Alternatively look for a .pid file for the script in your tmp directory, and kill (with SIGINT) the process with that PID.
ENVIRONMENT
pperl uses the PPERL_TMP_PATH environment variable to determine the directory where to store the files used for inter-process
communication. By default, the subdirectory .pperl of the user's home directory is used.
BUGS
The process does not reload when the script or modules change.
$^S is not represented identically with respect to perl, since your script will be run within an eval block
AUTHOR
Matt Sergeant, matt@sergeant.org. Copyright 2001 MessageLabs Ltd.
SEE ALSO
perl. perlrun.
perl v5.14.2 2011-11-15 PPERL(1p)