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Top Forums Shell Programming and Scripting want to get last year and month from the file Post 302523390 by Scott on Wednesday 18th of May 2011 06:54:09 PM
Old 05-18-2011
Sorry, I misread your question slightly.

Code:
logfileyearmonth=`echo $logfile | awk -F_ '{print $(NF-1)}'`

(I don't know where "$logfile" is set, and making no assumptions, $(NF-1) will give you the field you are looking for)

Code:
# Test, create some files:
echo "abc_cd_20110302_123423
abc_cd_ef_20110301_123423
abc_cd_ef_20110403_123423
abc_ef_20110401_123423" | xargs touch

$ ls * | awk -F_ '{print $(NF-1)}'
20110302
20110301
20110403
20110401

 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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