Hi All,
I want to find the previous day's date and store that in a variable, which will be usuful for further processing.
Any help please.
Regards,
raju (4 Replies)
Hello,
I wanted to display the month for previous day date. Like, today date is 18-Nov-2008. So the previous date is 17-Nov-2008. The output should be November.
If the today date is 1-DEC-2008, then output should be NOVEMBER.
If the today date is 1-JAN-2008, then output should be DECEMBER.... (4 Replies)
I have a problem of Finding Day of the week from date, but i need to do it within awk On SOLARIS
Input:20101007(YYYYMMDD)
Output:Thursday
kindly provide suggestions.
Thanks in advance (8 Replies)
hi there
I have file names in different format as below
triss_20111117_fxcb.csv
triss_fxcb_20111117.csv
xpnl_hypo_reu_miplvdone_11172011.csv
xpnl_hypo_reu_miplvdone_11-17-2011.csv
xpnl_hypo_reu_miplvdone_20111117.csv
xpnl_hypo_reu_miplvdone_20111117xfb.csv... (10 Replies)
Dear all,
I have 2 questions.
I have a file with many rows which has date of the format YYYYMMDD.
1. I need to change the date to that weeks friday date(Ex: 20120716(monday) to 20120720). Satuday/Sunday has to be changed to next week friday date too.
2. After converting the date to... (10 Replies)
Ok, the title is confusing i know, but it is a weird question.
I have a bash script running on Centos5.8 and want to find a better way to do some date manipulation. What i am trying to do is get 3 days of files (day before, that day, and day after), concatenate the three files and pass them on... (2 Replies)
I have requirment to get last date of previous month and the first date of previous 4th month:
Example:
Current date: 20130320 (yyyymmdd)
Last date of previous month: 20130228 (yyyymmdd)
First date of previous 4th month: 20121101 (yyyymmdd)
In my shell --date, -d, -v switches are not... (3 Replies)
Hi Experts,
i am using the below code get the date of previous day.
#!/usr/bin/ksh
datestamp=`date '+%Y%m%d'`
yest=$((datestamp -1))
echo $yest
When i execute the code i am getting output as:
20130715
What i am trying here is, based on the date passed i am fetching previus day's... (0 Replies)
Legends,
i need to get previous day using date command.
Can you please help.
sdosanjh:/home> date +%m%d%y
011514
i tried -d '-1 day' but it is not working (5 Replies)
I Have text like
XXX_20190908.csv.gz need to replace Only date in this format with current date every day
Thanks! (1 Reply)
Discussion started by: yamasani1991
1 Replies
LEARN ABOUT PHP
px_timestamp2string
PX_TIMESTAMP2STRING(3)PX_TIMESTAMP2STRING(3)px_timestamp2string - Converts the timestamp into a string.SYNOPSIS
string px_timestamp2string (resource $pxdoc, float $value, string $format)
DESCRIPTION
Turns a timestamp as it stored in the paradox file into human readable format. Paradox timestamps are the number of miliseconds since
0001-01-02. This function is just for convenience. It can be easily replaced by some math and the calendar functions as demonstrated in the
following example.
PARAMETERS
o $pxdoc
- Resource identifier of the paradox database.
o $value
- Value as stored in paradox database field of type PX_FIELD_TIME, or PX_FIELD_TIMESTAMP.
o $format
- String format similar to the format used by date(3). The placeholders support by this function is a subset of those supported by
date(3) (Y, y, m, n, d, j, H, h, G, g, i, s, A, a, L).
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
Turn a paradox timestamp into a human readable form
<?php
$px = px_new();
/* make up a date as it could be stored in */
/* a date field of a paradox db. */
/* 700000 days since 1.1.0000. */
$days = 700000;
/* Use the calendar functions to print a */
/* human readable format of the date */
echo jdtogregorian($days+1721425)."
";
/* Turn it into a timestamp as it stored in a paradox database */
/* Timestamps are stored in miliseconds since 0001-01-02 */
$stamp = $days * 86400.0 * 1000.0;
/* Add one hour */
$stamp += 3600000.0;
/* The following will output '7/15/1917 01:00:00'. */
echo px_timestamp2string($px, $stamp, "n/d/Y H:i:s")."
";
px_delete($px);
?>
The above example will output:
7/15/1917
7/15/1917 01:00:00
The Julian day count as passed to jdtogregorian(3) has a different base of 1.1.4714 b.c. and must therefore be calculated by adding
1721425 to the day count used in the paradox file. Turning the day count into a timestamp is easily done by multiplying with 86400000.0 to
obtain miliseconds.
SEE ALSO px_date2string(3), jdtogregorian(3).
PHP Documentation Group PX_TIMESTAMP2STRING(3)