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Top Forums Programming Finding items that occur more than once in a vector Post 302521943 by Corona688 on Thursday 12th of May 2011 10:45:49 PM
Old 05-12-2011
Quote:
Originally Posted by LMHmedchem
That's interesting, the cpp reference page gives "operator[]" as element access. I wonder what they mean by that.
It means what it says, you access elements with it, just like [] accesses elements in a vector. But unlike a vector, it's valid to access elements that don't exist yet! Do so and it'll just create it for you with default values(0 for atomic types). So if you did this the naive way on a map containing elements 0, 1, and 2:

Code:
for(n=0; n<1000; n++)
{
        if(mymap[n]) printf("Element %d exists %d times\n", mymap[n]);
}

...it'd create elements 3 through 999 for you and return their newly-created values of zero. Probably not what you want Smilie But an iterator will only give you elements that actually exist.
Quote:
I assume you can also use .find()?
Yes. I think map uses a list container internally. It's not a hash table.
 

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lreplace(1T)						       Tcl Built-In Commands						      lreplace(1T)

__________________________________________________________________________________________________________________________________________________

NAME
lreplace - Replace elements in a list with new elements SYNOPSIS
lreplace list first last ?element element ...? _________________________________________________________________ DESCRIPTION
lreplace returns a new list formed by replacing one or more elements of list with the element arguments. first and last specify the first and last index of the range of elements to replace. 0 refers to the first element of the list, and end (or any abbreviation of it) may be used to refer to the last element of the list. If list is empty, then first and last are ignored. If first is less than zero, it is considered to refer to the first element of the list. For non-empty lists, the element indicated by first must exist. If last is less than zero but greater than first, then any specified elements will be prepended to the list. If last is less than first then no elements are deleted; the new elements are simply inserted before first. The element arguments specify zero or more new arguments to be added to the list in place of those that were deleted. Each element argu- ment will become a separate element of the list. If no element arguments are specified, then the elements between first and last are sim- ply deleted. If list is empty, any element arguments are added to the end of the list. EXAMPLES
Replacing an element of a list with another: % lreplace {a b c d e} 1 1 foo a foo c d e Replacing two elements of a list with three: % lreplace {a b c d e} 1 2 three more elements a three more elements d e Deleting the last element from a list in a variable: % set var {a b c d e} a b c d e % set var [lreplace $var end end] a b c d SEE ALSO
list(1T), lappend(1T), lindex(1T), linsert(1T), llength(1T), lsearch(1T), lset(1T), lrange(1T), lsort(1T) | KEYWORDS
element, list, replace ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +--------------------+-----------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +--------------------+-----------------+ |Availability | SUNWTcl | +--------------------+-----------------+ |Interface Stability | Uncommitted | +--------------------+-----------------+ NOTES
Source for Tcl is available on http://opensolaris.org. Tcl 7.4 lreplace(1T)
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