I think the correct output in this case should be:
Because you cannot determine whether first record (IMAGINE) is correct or not, as you don't have previous record to analyze response. Try this script:
Run it like this: ./script.pl your_file
Hi,
I have below awk statement and I need to convert the second field ( substr($0,8,6))from minutes to hours with 2 decimail place. How can I achieve this?
/usr/bin/awk '{print substr($0,23,4),substr($0,8,6)}' /tmp/MANAGER_LIST.$$ >> /tmp/NEWMANAGER_LIST.$$
Thanks for any help! (4 Replies)
i have a line like this in my script
IP=`get_IP <hostname> | awk '{ print $1 }'
echo $IP
the problem is get_IP <hostname> returns data formated as follows:
ip 1.1.1.1 name server_name
the code above returns
1.1.1.1 server_name and i just need the 1.1.1.1
I have tried to add "|... (5 Replies)
Is there any awk command to calculate P Value ?(Probability)
Is it possib;e to calculate P va;ue for this data for ex?
7.891284
8.148193
7.749575
7.958188
7.887702
7.714877
8.141548
7.51845
8.27736
7.929853
7.92456
8.249126
7.989113
8.012573
8.351206 (2 Replies)
Hello, I have the following file, but one of his columns is not in place, and tried with SED and AWK, how I can correct format?
In the second line break is wrong, and puts it after the first column of next line
I would appreciate if you could guide me on the subject. (4 Replies)
Hello,
I have been trying to use an awk script to parse out correct and incorrect answers in a simple tab-delimited text file. I am trying to compare the user's response to the stimulus presented (in this case, an arrow pointing left or right; e.g., "<--" vs. "-->"). I have the data for the... (6 Replies)
I have this input.|user1 |10.10.10.10 |23|046|1726 (212) |0
|user2 |10.10.10.11 |23|046|43 (17) |0
|test |10.10.10.12 |23|046|45 (10) |0
|test1 |10.10.10.13 |23|046|89 (32) |0
I need to get the data for a user like thisuser1 1726
user2 43
test 45
test1 89... (11 Replies)
Hi all,
I think so I’m getting the result is wrong, while using following awk commend,
colval=$(awk 'FNR>1 && NR==FNR{a=$4;next;} FNR>1 {a+=$4; print $2"\t"a/3}'
filename_f.tsv filename_f2.tsv filename_f3.tsv)
echo $colval >> Result.tsv
it’s doing the condition 2 times, first result... (5 Replies)
Hi everyone,
The following piece of awk code works fine if I use eval builtin
var='$1,$2'
ps | eval "awk '{print $var}'"
But when I try to knock off eval and use awk variable as substitute then I am not getting the expected result
ps | awk -v v1=$var '{print v1}' # output is $1,$2
ps |... (4 Replies)
The awk below runs and produces the following output on the file2. This is just an example of the format as the file is ~14MB. file1.txt is attached. I am trying to count the ids that match between the two files and out the ids that are missing. Thank you :).
file2
970 NM_213590 ... (2 Replies)
Discussion started by: cmccabe
2 Replies
LEARN ABOUT SUSE
net::ldap::control::sortresult
Net::LDAP::Control::SortResult(3) User Contributed Perl Documentation Net::LDAP::Control::SortResult(3)NAME
Net::LDAP::Control::SortResult - Server Side Sort (SSS) result control object
SYNOPSIS
use Net::LDAP::Control::Sort;
use Net::LDAP::Constant qw(LDAP_CONTROL_SORTRESULT);
use Net::LDAP::Util qw(ldap_error_name);
$sort = Net::LDAP::Control::Sort->new(
order => "cn -age"
);
$mesg = $ldap->search( @args, control => [ $sort ]);
($resp) = $mesg->control( LDAP_CONTROL_SORTRESULT );
if ($resp) {
if ($resp->result) {
my $attr = $resp->attr;
print "Problem sorting, ",ldap_error_name($resp->result);
print " ($attr)" if $attr;
print "
";
}
else {
print "Results are sorted
";
}
}
else {
print "Server does not support sorting
";
}
DESCRIPTION
"Net::LDAP::Control::SortResult" is a sub-class of Net::LDAP::Control. It provides a class for manipulating the LDAP sort request control
1.2.840.113556.1.4.474 as defined in RFC-2891
A sort result control will be returned by the server in response to a search with a Server Side Sort control. If a sort result control is
not returned then the user may assume that the server does not support sorting and the results are not sorted.
CONSTRUCTOR ARGUMENTS
attr
If "result" indicates that there was a problem with sorting and that problem was due to one of the attributes specified in the sort
control. "attr" is set to the name of the attribute causing the problem.
result
This is the result code that describes if the sort operation was sucessful. If will be one of the result codes describes below.
METHODS
As with Net::LDAP::Control each constructor argument described above is also avaliable as a method on the object which will return the
current value for the attribute if called without an argument, and set a new value for the attribute if called with an argument.
RESULT CODES
Possible results from a sort request are listed below. See Net::LDAP::Constant for a definition of each.
LDAP_SUCCESS
LDAP_OPERATIONS_ERROR
LDAP_TIMELIMIT_EXCEEDED
LDAP_STRONG_AUTH_REQUIRED
LDAP_ADMIN_LIMIT_EXCEEDED
LDAP_NO_SUCH_ATTRIBUTE
LDAP_INAPPROPRIATE_MATCHING
LDAP_INSUFFICIENT_ACCESS
LDAP_BUSY
LDAP_UNWILLING_TO_PERFORM
LDAP_OTHER
SEE ALSO
Net::LDAP, Net::LDAP::Control::Sort, Net::LDAP::Control, http://ww.ietf.org/rfc/rfc2891.txt
AUTHOR
Graham Barr <gbarr@pobox.com>
Please report any bugs, or post any suggestions, to the perl-ldap mailing list <perl-ldap@perl.org>
COPYRIGHT
Copyright (c) 1999-2004 Graham Barr. All rights reserved. This program is free software; you can redistribute it and/or modify it under the
same terms as Perl itself.
perl v5.12.1 2010-03-12 Net::LDAP::Control::SortResult(3)