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Full Discussion: STDIN and STDOUT
Top Forums UNIX for Dummies Questions & Answers STDIN and STDOUT Post 302521367 by eightball on Wednesday 11th of May 2011 04:52:23 AM
Old 05-11-2011
STDIN and STDOUT

Hallo,

i have a script like:

PHP Code:
if [$1] ;then
echo "OK"

else 
echo 
"ERROR $2 is missing"

fi;

if [$
2];then
touch 
$2

fi
;

if [$
2];then
 cat 
$1  grep xy > $2

fi

but i must do that with STDIN and STDOUT, when i want to run the script it must not give parameters. It must run like
PHP Code:
cat zz | ./rrr.sh zz_solution.txt 
 

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PHP_LOGO_GUID(3)							 1							  PHP_LOGO_GUID(3)

php_logo_guid - Gets the logo guid

SYNOPSIS
string php_logo_guid (void ) DESCRIPTION
This function returns the ID which can be used to display the PHP logo using the built-in image. Logo is displayed only if expose_php is On. Warning This function has been DEPRECATED and REMOVED as of PHP 5.5.0. RETURN VALUES
Returns PHPE9568F34-D428-11d2-A769-00AA001ACF42. CHANGELOG
+--------+---------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------+ | 5.5.0 | | | | | | | php_logo_guid(3) has been removed from PHP. | | | | +--------+---------------------------------------------+ EXAMPLES
Example #1 php_logo_guid(3) example <?php echo '<img src="' . $_SERVER['PHP_SELF'] . '?=' . php_logo_guid() . '" alt="PHP Logo !" />'; ?> SEE ALSO
phpinfo(3), phpversion(3), phpcredits(3), zend_logo_guid(3). PHP Documentation Group PHP_LOGO_GUID(3)
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