Sponsored Content
Top Forums UNIX for Dummies Questions & Answers sed or awk - removing part of line? Post 302520055 by vgersh99 on Thursday 5th of May 2011 04:44:06 PM
Old 05-05-2011
Code:
sed -n '/ 603-/s/ 603-/ /p' myFile | sort

 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

removing parts of a line with SED

hi, i'm trying to erase all the characters after, and including, the first test test Output: test1 test2 test3 this is what I tried, but didn't work sed "s/*//" file > testfilename any suggestions? thanks, gammmaman (2 Replies)
Discussion started by: gammaman
2 Replies

2. Shell Programming and Scripting

removing a line containing a pattern in sed

i need to use sed to remove an entire line containing a pattern stored in a variable say $var1 this var1 will be a URL and will therefore contain slashes any help would be greatly appreciated (1 Reply)
Discussion started by: Fire_Storm
1 Replies

3. Shell Programming and Scripting

Getting sed to work on part of a line

I been trying to get this right. I have trying to get rid of spaces in between the character < and the character >. Everytime I try, sed gets too greedy and do the whole line. Ex. < T AG 1> Hello, how are you doing? <Tag 2> I am doing fine. I want this: <TAG1> Hello, how are you... (6 Replies)
Discussion started by: quixoticking11
6 Replies

4. Shell Programming and Scripting

Replace part of a line with sed/awk

Hello I have a document and in this document I have several occurrence of "VAR == xxxxxxx" and xxxxx can be anything. I don't know what it is. I want to replace the 'xxxxx's with something I know. What I know however, is the line numbers of the VAR =='s in the file. How can I replace... (1 Reply)
Discussion started by: alirezan
1 Replies

5. Shell Programming and Scripting

Sed question (Removing a line of text)

I am working with bash on HP-UX server at school. As practice for scripting, I am trying to make a pretend server admin script that adds a user to the system, deletes a user from the system, and lists all users of the pretend system. I have accomplished this with a select loop. Adding users, and... (2 Replies)
Discussion started by: masterscout1977
2 Replies

6. Shell Programming and Scripting

change part of a line with sed

Hi gurus, I'd like to change this complete line on a file: BAN_COMMAND="/etc/apf/apf -d $ATTACK_HOST {bfd.$MOD}" to this one: BAN_COMMAND="/sbin/iptables -A INPUT -s $ATTACK_HOST -j DROP" I've tried a lot without any successful . :( thanks in advance Israel. (2 Replies)
Discussion started by: iga3725
2 Replies

7. Shell Programming and Scripting

Using Sed to remove part of line with regex

Greetings everyone. Right now I am working on a script to be used during automated deployment of servers. What I have to do is remove localhost.localdomain and localhost6.localdomain6 from the /etc/hosts file. Simple, right? Except most of the examples I've found using sed want to delete the entire... (4 Replies)
Discussion started by: msarro
4 Replies

8. UNIX for Dummies Questions & Answers

Removing end of line using SED

Hello Friends, How can I remove the last two values of this line using sed John Carey:507-699-5368:29 Albert way, Edmonton, AL 25638:9/3/90:45900 The result should look like this: John Carey:507-699-5368:29 Albert way, Edmonton, AL 25638 (3 Replies)
Discussion started by: humkhn
3 Replies

9. Shell Programming and Scripting

sed removing until end of line

All: Can somebody help me out with a sed command, which removes the the first occurance of ')' until the end of the line If I have the following input ... (5 Replies)
Discussion started by: BeefStu
5 Replies

10. Shell Programming and Scripting

sed command for picking a part of line

Hello Friends I want to use sed command to pick a part of line. FOr example I only need the /home_put1/bidds/myfo part of following line fish://ulavet@rits1.ula.com.tr/home_put1/bidds/myfo How can I do this bu using sed command ? (2 Replies)
Discussion started by: rpf
2 Replies
sort(3pm)						 Perl Programmers Reference Guide						 sort(3pm)

NAME
sort - perl pragma to control sort() behaviour SYNOPSIS
use sort 'stable'; # guarantee stability use sort '_quicksort'; # use a quicksort algorithm use sort '_mergesort'; # use a mergesort algorithm use sort 'defaults'; # revert to default behavior no sort 'stable'; # stability not important use sort '_qsort'; # alias for quicksort my $current; BEGIN { $current = sort::current(); # identify prevailing algorithm } DESCRIPTION
With the "sort" pragma you can control the behaviour of the builtin "sort()" function. In Perl versions 5.6 and earlier the quicksort algorithm was used to implement "sort()", but in Perl 5.8 a mergesort algorithm was also made available, mainly to guarantee worst case O(N log N) behaviour: the worst case of quicksort is O(N**2). In Perl 5.8 and later, quicksort defends against quadratic behaviour by shuffling large arrays before sorting. A stable sort means that for records that compare equal, the original input ordering is preserved. Mergesort is stable, quicksort is not. Stability will matter only if elements that compare equal can be distinguished in some other way. That means that simple numerical and lexical sorts do not profit from stability, since equal elements are indistinguishable. However, with a comparison such as { substr($a, 0, 3) cmp substr($b, 0, 3) } stability might matter because elements that compare equal on the first 3 characters may be distinguished based on subsequent characters. In Perl 5.8 and later, quicksort can be stabilized, but doing so will add overhead, so it should only be done if it matters. The best algorithm depends on many things. On average, mergesort does fewer comparisons than quicksort, so it may be better when complicated comparison routines are used. Mergesort also takes advantage of pre-existing order, so it would be favored for using "sort()" to merge several sorted arrays. On the other hand, quicksort is often faster for small arrays, and on arrays of a few distinct values, repeated many times. You can force the choice of algorithm with this pragma, but this feels heavy-handed, so the subpragmas beginning with a "_" may not persist beyond Perl 5.8. The default algorithm is mergesort, which will be stable even if you do not explicitly demand it. But the stability of the default sort is a side-effect that could change in later versions. If stability is important, be sure to say so with a use sort 'stable'; The "no sort" pragma doesn't forbid what follows, it just leaves the choice open. Thus, after no sort qw(_mergesort stable); a mergesort, which happens to be stable, will be employed anyway. Note that no sort "_quicksort"; no sort "_mergesort"; have exactly the same effect, leaving the choice of sort algorithm open. CAVEATS
As of Perl 5.10, this pragma is lexically scoped and takes effect at compile time. In earlier versions its effect was global and took effect at run-time; the documentation suggested using "eval()" to change the behaviour: { eval 'use sort qw(defaults _quicksort)'; # force quicksort eval 'no sort "stable"'; # stability not wanted print sort::current . " "; @a = sort @b; eval 'use sort "defaults"'; # clean up, for others } { eval 'use sort qw(defaults stable)'; # force stability print sort::current . " "; @c = sort @d; eval 'use sort "defaults"'; # clean up, for others } Such code no longer has the desired effect, for two reasons. Firstly, the use of "eval()" means that the sorting algorithm is not changed until runtime, by which time it's too late to have any effect. Secondly, "sort::current" is also called at run-time, when in fact the compile-time value of "sort::current" is the one that matters. So now this code would be written: { use sort qw(defaults _quicksort); # force quicksort no sort "stable"; # stability not wanted my $current; BEGIN { $current = print sort::current; } print "$current "; @a = sort @b; # Pragmas go out of scope at the end of the block } { use sort qw(defaults stable); # force stability my $current; BEGIN { $current = print sort::current; } print "$current "; @c = sort @d; } perl v5.16.3 2013-03-04 sort(3pm)
All times are GMT -4. The time now is 10:48 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy