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Top Forums UNIX for Dummies Questions & Answers sed or awk - removing part of line? Post 302520049 by alis on Thursday 5th of May 2011 04:32:12 PM
Old 05-05-2011
is there a way to do this using sed?
 

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Perl::Critic::Policy::RegularExpressions::RequireLineBouUseryContributedPerl::Critic::Policy::RegularExpressions::RequireLineBoundaryMatching(3pm)

NAME
Perl::Critic::Policy::RegularExpressions::RequireLineBoundaryMatching - Always use the "/m" modifier with regular expressions. AFFILIATION
This Policy is part of the core Perl::Critic distribution. DESCRIPTION
Folks coming from a "sed" or "awk" background tend to assume that '$' and '^' match the beginning and end of the line, rather than then beginning and end of the string. Adding the '/m' flag to your regex makes it behave as most people expect it should. my $match = m{ ^ $pattern $ }x; #not ok my $match = m{ ^ $pattern $ }xm; #ok CONFIGURATION
This Policy is not configurable except for the standard options. NOTES
For common regular expressions like e-mail addresses, phone numbers, dates, etc., have a look at the Regexp::Common module. Also, be cautions about slapping modifier flags onto existing regular expressions, as they can drastically alter their meaning. See <http://www.perlmonks.org/?node_id=484238> for an interesting discussion on the effects of blindly modifying regular expression flags. AUTHOR
Jeffrey Ryan Thalhammer <jeff@imaginative-software.com> COPYRIGHT
Copyright (c) 2005-2011 Imaginative Software Systems. All rights reserved. This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself. The full text of this license can be found in the LICENSE file included with this module. perl v5.14.2 2012Perl::Critic::Policy::RegularExpressions::RequireLineBoundaryMatching(3pm)
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