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Top Forums Shell Programming and Scripting How to check for a Numeric Value? Post 302519672 by jim mcnamara on Wednesday 4th of May 2011 04:15:32 PM
Old 05-04-2011
one way:
Code:
var=123.1
check=$(echo "$var" | tr -d '[:digit:]' | tr -d '.')
if [  -z "$check" ]; then
      echo 'is all digits'
else
      echo 'is not all digits'
fi

These 2 Users Gave Thanks to jim mcnamara For This Post:
 

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CTYPE_XDIGIT(3) 							 1							   CTYPE_XDIGIT(3)

ctype_xdigit - Check for character(s) representing a hexadecimal digit

SYNOPSIS
bool ctype_xdigit (string $text) DESCRIPTION
Checks if all of the characters in the provided string, $text, are hexadecimal 'digits'. PARAMETERS
o $text - The tested string. RETURN VALUES
Returns TRUE if every character in $text is a hexadecimal 'digit', that is a decimal digit or a character from [A-Fa-f] , FALSE otherwise. EXAMPLES
Example #1 A ctype_xdigit(3) example <?php $strings = array('AB10BC99', 'AR1012', 'ab12bc99'); foreach ($strings as $testcase) { if (ctype_xdigit($testcase)) { echo "The string $testcase consists of all hexadecimal digits. "; } else { echo "The string $testcase does not consist of all hexadecimal digits. "; } } ?> The above example will output: The string AB10BC99 consists of all hexadecimal digits. The string AR1012 does not consist of all hexadecimal digits. The string ab12bc99 consists of all hexadecimal digits. NOTES
Note If an integer between -128 and 255 inclusive is provided, it is interpreted as the ASCII value of a single character (negative val- ues have 256 added in order to allow characters in the Extended ASCII range). Any other integer is interpreted as a string contain- ing the decimal digits of the integer. SEE ALSO
ctype_digit(3). PHP Documentation Group CTYPE_XDIGIT(3)
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