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Full Discussion: Sorting based on multiple delimiters
Top Forums Shell Programming and Scripting Sorting based on multiple delimiters Post 302519077 by rdcwayx on Tuesday 3rd of May 2011 02:32:28 AM
Old 05-03-2011
Quote:
Originally Posted by gimley
Hello,
I tested the file and what I get is the message
0 delimiters
followed by the full set of sample test data.
I checked the script abd the syntax shows that the files should be sorted as per number of delimiters.
What has gone wrong ?
I am enclosing the testdata as a zip file.
Many thanks
No problem I found.

If you run the awk in Solaris, please replace the command with nawk or /usr/xpg4/bin/awk
Code:
awk -F = 'NR==1{max=NF;min=NF}
         {max=(max>NF)?max:NF;min=(min<NF)?min:NF;a[NF]=(a[NF]=="")?$0:a[NF] ORS $0}
    END{for (i=max;i>=min;i--) {if (a[i]!="") print i-1 " delimiters" ORS a[i]}}' test |head -10

6 delimiters
pathan=inayat=khan=rashid=khan=sahebzadi=m
shiv=ram=tandale=ganesh=laxman=hirabai=m
5 delimiters
gore=bibi=sakina=irfanali=tayeba=f
jamadar=aves=ahmed=ashfaque=sherbano=m
ram=tandale=ganesh=laxman=hirabai=m
4 delimiters
kale=amita=bhanudas=shobha=f
lande=amit=chandrabhan=asha=m

---------- Post updated at 04:32 PM ---------- Previous update was at 04:25 PM ----------

Quote:
Originally Posted by kevintse
Try this:
Code:
awk -F= '{print NF, $0}' infile | sort -k1 -nr | awk '!d||$1!=d{d=$1; print d-1 " delimiters"}{print $2}'

Clever way.

little adjust (!a[$1]++) to look better, and -k1 is useless.
Code:
awk -F= '{print NF, $0}' infile | sort -nr |awk '!a[$1]++ {print $1-1 " delimiters" }{print $2}'

 

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LEARN ABOUT MINIX

paste

PASTE(1)						      General Commands Manual							  PASTE(1)

NAME

       paste - paste multiple files together

SYNOPSIS

       paste [-s] [-d list] file...

OPTIONS

       -d     Set delimiter used to separate columns to list.

       -s     Print files sequentially, file k on line k.

EXAMPLES

       paste file1 file2   # Print file1 in col 1, file2 in col 2

       paste -s f1 f2	   # Print f1 on line 1 and f2 on line 2

       paste -d : file1 file2
			   # Print the lines separated by a colon

DESCRIPTION

       Paste  concatenates  corresponding  lines of the given input files and writes them to standard output. The lines of the different files are
       separated by the delimiters given with the option -s. If no list is given, a tab is substituted for every linefeed, except  the	last  one.
       If  end-of-file	is hit on an input file, subsequent lines are empty.  Suppose a set of k files each has one word per line.  Then the paste
       output will have k columns, with the contents of file j in column j.  If the -s flag is given, then the first file is on line 1, the second
       file on line 2, etc.  In effect, -s turns the output sideways.

       If  a list of delimiters is given, they are used in turn.  The C escape sequences 
, 	, \, and  are used for linefeed, tab, backslash,
       and the null string, respectively.

																	  PASTE(1)
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