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Top Forums Shell Programming and Scripting Script for taking backup of desktop files. Post 302516353 by paragnehete on Friday 22nd of April 2011 04:54:27 PM
Old 04-22-2011
I made this script......



Code:
#! /bin/bash
 
# Variables
location=/home/dr/parag.n/Desktop
directory=*
backuplocation=/home/dr/parag.n
log=/home/dr/parag.n/backup.log
 
echo -e “\nBackup started: `date`” >> $log
 
if [ -d $backuplocation ]; then
 
mkdir -p $backuplocation/`date +%y-%m-%d`
cd $location
tar -zcvf $backuplocation/`date +%y-%m-%d`/Desktop-Files.`date  +%H-%M-%S`.tar.gz $directory
rm -fr *
echo ” completed: `date`” >> $log
mv $log $backuplocation/backup.log
echo -e “\n — Backup completed –\n”;
else
echo ” FAILED: `date`” >> $log
echo -e “\n– WARNING: –”
echo -e “– BACKUP FAILED –\n”;
fi



In this "parag.n" is my home directory. But I have many users. How can i take backup of all of them? & How could i get a mail after finishing backup?

Moderator's Comments:
Mod Comment Please use [CODE] tags when posting listings, ...

Last edited by pludi; 04-23-2011 at 09:31 AM..
 

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DATETIME.SUB(3) 							 1							   DATETIME.SUB(3)

DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_sub (DateTime $object, DateInterval $interval) Subtracts the specified DateInterval object from the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.sub(3) example Object oriented style <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-20'); date_sub($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-10 Example #2 Further DateTime.sub(3) examples <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-19 13:59:30 1992-08-15 19:56:58 Example #3 Beware when subtracting months <?php $date = new DateTime('2001-04-30'); $interval = new DateInterval('P1M'); $date->sub($interval); echo $date->format('Y-m-d') . " "; $date->sub($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-03-30 2001-03-02 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.add(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.SUB(3)
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