Hi,
I have hundered's of files of the name
CMP_PORT_IN_P200903271623042437_20090328122430_err.xml in error directory of todays date ie 20090328 and in the file name 5th field specifies date only now i want to move all files of 20090328 to another directory i.e reprocess directory.
So... (3 Replies)
Hi Guys,
I need to count files in a dir which were updated yesterday.
ls -lth | grep -i 'Jul 7' | wc -l
The dir holds files of last 15 days and total count is as 2067476.
Is it efficient to count the files using perl? I have developed the following perl script making use of system().
Can... (3 Replies)
Hello!!
I have directories from 2008, with files in them. I want to create a script that will find the directoried from 2008 (example directory:
drwxr-xr-x 2 isplan users 1024 Nov 21 2008 FILES_112108), delete the files within those directories and then delete the directories... (3 Replies)
Hi, I am a unix newbie.I need to write a shell script to move my oracle READ WRITE datafiles from one serevr to another. I need to move it from /u01/oradata/W1KK/.. to /u01/oradata/W2KK,
/u02/oradata/W1KK/.. to /u02/oradata/W2KK.
That is, I actaully am moving my datafiles from one database to... (2 Replies)
Can someone please guide me how I can get a single line for each directory:
ls -ltrR|awk '/(\.\/)()*/ { print $0;d=$0;n=0;} /^-*/ { n=n+1; print d,n } '
What I'm trying to get is
webconsole: 23
logs: 34
logd: 344
Regards,
BB (3 Replies)
I am very new to unix as well as shell scripting.
I have to write a script for the following requirement. In have to list all the files in directory and its sub directories along with file path and size of the file
Please help me in this regard and many thanks in advance. (3 Replies)
Dear Members,
I have a list of xml files like
abc.xml.table
prq.xml.table
...
..
.
in a txt file.
Now I have to search the file(s) in all directories and sub-directories and print the full path of file in a output txt file.
Please help me with the script or command to do so.
... (11 Replies)
I have searched this quite a long time but couldn't find the right method for me to use. I need to assign read write permission to the user for specific directories and it's sub directories and files. I do not want to use ACL. I do not want to assign user the same group of that directories too.... (0 Replies)
Discussion started by: blinkingdan
0 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)