bash variable (set via awk+sed) not working as expected Post: 302515360

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Top Forums Shell Programming and Scripting bash variable (set via awk+sed) not working as expected Post 302515360 by michaelrozar17 on Wednesday 20th of April 2011 02:41:41 AM

04-20-2011

Registered User

Quote:

Originally Posted by creativedynamo

servername=$(awk -v FS=\/ '{ print $8 }' blah3.txt | sed 's/\./-/g' | awk -v FS=\- '{ print $1 }')

# Now printing data out again with our new column added.
awk -v serv=$servername -v mtime=$mtime -v mdate=$mdate '{ print mdate,mtime,$1,$2,serv,$3,$4 }' blah3.txt

done

Are you sure that your printing the right column. The above awk command prints the 8th column.Also the command could be shortened as

Code:

servername=$(awk -F\/ '{ print $7 }' blah3.txt | awk  FS=\. '{ print $1 }')

Also as you have said that there is no value while it loops the 2nd time check the for loop values' 2nd iteration i.e crit and additionally before running the whole script try each command after curl manually and check if it gives the expected output or not. Alternatively you can also use set -x on top of the script to view the script output in de-bug mode.

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