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Top Forums Shell Programming and Scripting Running Multiple scripts based on file size. Post 302515223 by ahamed101 on Tuesday 19th of April 2011 12:53:55 PM
Old 04-19-2011
function err{} - just a function to print the error message if any. Else we will have to print the error message everywhere. The arguments are $1 - return value;success 0;failure > 0 and $2 - Any message you want to print.

So when you do the below call
Code:
$srcloc/1.sh err "$?" "1.sh failed"

First argument will be the return value of the execution of the script 1.sh. Second argument will be the error message it will print if at all the script failed.

Coming to the error part - can you paste the exact error your getting.
Try this code
Code:
if [ "$fileSize" -eq 0 ] 
then   
err "1" "blr_src.txt is empty" 
fi

May be fileSize is not populated correctly. Debug it by printing the values or running it in debug mode using -x option from command line. Check the path of blr_src.txt, may thats incorrect.

regards,
Ahamed

Last edited by ahamed101; 04-19-2011 at 01:54 PM.. Reason: code tags
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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