The second backslash, before the right-bracket, is not necessary since the right-bracket is not a special character unless it's matching an opening left-bracket to form a bracket expression. And even when building a bracket expression, since a backslash is not special within a bracket expression, it cannot be used to quote a right bracket. Further, the \] yields an undefined sequence which can be treated differently depending on the regular expression engine implementation.
Quote:
Originally Posted by wpfontenot
Code:
C:\WINDOWS\NTDS\ntds.dit
Each backslash in that pathname, since it's intended to be taken literally, needs to be itself backslash escaped. Also, if you want to match that filename exactly, you should quote the dot before the file extension so it matches a literal dot instead of any character.
Code:
C:\\WINDOWS\\NTDS\\ntds\.dit
Regards,
Alister
---------- Post updated at 12:55 AM ---------- Previous update was at 12:51 AM ----------
Quote:
Originally Posted by kevintse
I think the problem is [-A-Za-z0-9_.]*, you have a dot within the square brackets, and that would match any characters, spaces included, so that pattern would match the whole string.
That's incorrect. A dot within a bracket expression is not special. The same goes for *, [, and \. They all lose their special meaning within a bracket expression.
i can only find the first occurance of a pattern how do i set it to loop untill all occurances have changed.
#! /usr/bin/perl
use POSIX;
open (DFH_FILE, "./dfh") or die "Can not read file ($!)";
foreach (<DFH_FILE>) {
if ($_ !~ /^#|^$/) {
chomp;
... (1 Reply)
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494 8134 A023 A024
49 812A 9871 9872
492 A961 A962 A963
491 0B77 0B78 0B79
495 0B7A 0B7B 0B7C
4949 WER9 444L 999O
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