I'm using gensub function with regexp back reference feature, This feature within gensub works something like this:
gensub(/regexp/, replacement, how [, target], where
Code:
regexp: Pattern you want to search
Replacement: The replacement of "pattern"
how="g": Indicates it replaces all matches of regexp with replacement
target: If no target is supplied, $0 is used
To use back reference you need to suround between parentheses "(" and ")" the regexp you want to remember and
all that is outside the back reference parentheses won't be buffered or remembered.
Code:
# back reference parentheses in red, regexp to be matched is inside them
gensub(/.*\((.*)\).*\(.*:(.*)\).*'\''(.*)'\''.*/ ....
1 2 3
Explaining first part of regexp:
Code:
.*\((.*)\)=.* plus\( plus (.*) plus \)
Where,
Code:
.* is to match: I. 2011/04/14 01:12:03. process\( is to match: ( the opening parentheses <<the literal "(" is escaped with \( >>
(.*) is to match: 130 = the content within the literal parentheses and to use back reference we suround with ()\) is to match: ) the closing parentheses <<the literal ")" is escaped with \) >>
and so on.
Then the 2nd back reference matches and remembers the string after ":" and before ")" in green(ESN:27723211621B01DJ68AG))
And the 3rd back reference is to match the substring between single quotes. Here, to match literal single quotes was needed to escape it
not only with \', but with'\''. This is single
quotes ' .. 'around \'.
After follow the same process to match the following part of the complete string, to remember the stored substrings
we use \\i in the order needed. I've used 3 backreference parentheses, then I remenber 3 backreference in the order
1,2,3, but it could be 3,1,2 or 3,3,1, or 3,2,1 etc, up to your needs. In this case with a space between them
"\\1 \\2 \\3".
Hope this helps.
Regards
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