Hello guys! It's orszhak and in my book I am currently studying incrementing values in c++ and it states thant I could do this to increment the value of nVariable
it states that I could also do this and assign the same value
but can't I also do this and assign the same value to the variable? here:
Or what about this
Anyways thanks guys!
I'm guessing you're confused on the concept of increment. += 2 adds two, it doesn't set it to two.
If that's not what you mean, I'm sorry, I don't understand your question.
I'm using the following command to test for certain characters in a script
echo "${1}" | grep '\$'
if (( ${?} == 0 ))
then
testing this script on the command line I have
ksh -x script1.sh "xxxx$xxxx"
this works fine but when I want to use
ksh -x script1.sh "xxxx $xxx"
the... (1 Reply)
I am looking for 8 variables in the following profile. I am looking to see if anyone could explain this for me better than the book I am using has been able to. There are 5 system, 2 aliases, and one editor. The profile is as follows:
# @(#)local.profile 1.8 99/03/26 SMI
stty istrip... (0 Replies)
Hi,
I am trying to do some mass replacements in lots of scripts, and using sed.
However sed doesn't seem to like to be able to dereference variables within the substitute clause. For example:
tab=newtable
cat f1 | sed 's/oldtable/$tab/g' doesn't work.
it would replace oldtable with the... (2 Replies)
Hi everybody, im trying to store a path "address" of a file in a variable, then IF the Address that the user entered INSIDE the variable is exist, do something, else echo invalid file address.
here's my code, but it's not working i dunno why:
$variable
cat > variable
#variable will contain... (4 Replies)
Hi
I am trying to find were to look for definitions of these variables; $0, $1, $2, $#, $$ , $*. I am not having much luck with my searching. Can anyone point me in the right direction?
Thanks, Doug (3 Replies)
I kind of found out the hard way that I am not able to manipulate the null value, the long silence that happens when there is no value returned.
I am looking for PIDs, and when there is no PID return, I wanted to handle this special scenario.
Here is my script.
#!/bin/bash
LAN_VARIABLE=... (7 Replies)
I am running some commands and I am trying to get an output into a variable. I am having problem when I try to put that value in while loop, it says integer value expected. What's the best way to accomplish this
remaining=$(symclone -sid XXX -f Clone_test query | grep MB | awk '{print... (1 Reply)
I have 2 scripts first script would call second script.
test1.sh
#!/bin/bash
logfile=`basename $0`.log
echo "First File" >> $logfile
TIME=`ls -lu array.ksh | awk '{print $6" "$7" "$8}'`
. /home/infrmtca/bin/Test/test2.sh
#/home/infrmtca/bin/Test/test2.sh
test2.sh
#!/bin/bash... (1 Reply)
Discussion started by: Ariean
1 Replies
LEARN ABOUT PHP
integer
integer(3pm) Perl Programmers Reference Guide integer(3pm)NAME
integer - Perl pragma to use integer arithmetic instead of floating point
SYNOPSIS
use integer;
$x = 10/3;
# $x is now 3, not 3.33333333333333333
DESCRIPTION
This tells the compiler to use integer operations from here to the end of the enclosing BLOCK. On many machines, this doesn't matter a
great deal for most computations, but on those without floating point hardware, it can make a big difference in performance.
Note that this only affects how most of the arithmetic and relational operators handle their operands and results, and not how all numbers
everywhere are treated. Specifically, "use integer;" has the effect that before computing the results of the arithmetic operators (+, -,
*, /, %, +=, -=, *=, /=, %=, and unary minus), the comparison operators (<, <=, >, >=, ==, !=, <=>), and the bitwise operators (|, &, ^,
<<, >>, |=, &=, ^=, <<=, >>=), the operands have their fractional portions truncated (or floored), and the result will have its fractional
portion truncated as well. In addition, the range of operands and results is restricted to that of familiar two's complement integers,
i.e., -(2**31) .. (2**31-1) on 32-bit architectures, and -(2**63) .. (2**63-1) on 64-bit architectures. For example, this code
use integer;
$x = 5.8;
$y = 2.5;
$z = 2.7;
$a = 2**31 - 1; # Largest positive integer on 32-bit machines
$, = ", ";
print $x, -$x, $x + $y, $x - $y, $x / $y, $x * $y, $y == $z, $a, $a + 1;
will print: 5.8, -5, 7, 3, 2, 10, 1, 2147483647, -2147483648
Note that $x is still printed as having its true non-integer value of 5.8 since it wasn't operated on. And note too the wrap-around from
the largest positive integer to the largest negative one. Also, arguments passed to functions and the values returned by them are not
affected by "use integer;". E.g.,
srand(1.5);
$, = ", ";
print sin(.5), cos(.5), atan2(1,2), sqrt(2), rand(10);
will give the same result with or without "use integer;" The power operator "**" is also not affected, so that 2 ** .5 is always the
square root of 2. Now, it so happens that the pre- and post- increment and decrement operators, ++ and --, are not affected by "use
integer;" either. Some may rightly consider this to be a bug -- but at least it's a long-standing one.
Finally, "use integer;" also has an additional affect on the bitwise operators. Normally, the operands and results are treated as unsigned
integers, but with "use integer;" the operands and results are signed. This means, among other things, that ~0 is -1, and -2 & -5 is -6.
Internally, native integer arithmetic (as provided by your C compiler) is used. This means that Perl's own semantics for arithmetic
operations may not be preserved. One common source of trouble is the modulus of negative numbers, which Perl does one way, but your
hardware may do another.
% perl -le 'print (4 % -3)'
-2
% perl -Minteger -le 'print (4 % -3)'
1
See "Pragmatic Modules" in perlmodlib, "Integer Arithmetic" in perlop
perl v5.12.1 2010-04-26 integer(3pm)