Sponsored Content
Full Discussion: Find directories by regex
Top Forums Shell Programming and Scripting Find directories by regex Post 302512754 by Corona688 on Monday 11th of April 2011 01:48:06 PM
Old 04-11-2011
Quote:
Originally Posted by ctsgnb
Stick with alister's suggestion, that's the best one (... the suggestion Smilie )
Sticking too many args in a for statement doesn't make too many args not be too many args. Neither does sticking 'find' in backticks make too many args not be too many args.

Just searching for directory names though, I don't think is likely to cause too many arguments.
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Find with RegEx

I have some files in unix ls -1 TMH.backend.tar.421E-03.Z TMH.backend.tar.421E-04.Z TMH.backend.tar.421E-05.Z TMH.backend.tar.421E-06.Z TMH.backend.tar.421E-07.Z TMH.backend.tar.421E-08.Z TMH.backend.tar.421E-08.Z.bak20081223164844 TMH.backend.tar.421E-09.Z... (1 Reply)
Discussion started by: on9west
1 Replies

2. Shell Programming and Scripting

How to find 777 permisson is there or not for Directories and sub-directories

Hi All, I am Oracle Apps Tech guy, I have a requirement to find 777 permission is there or not for all Folders and Sub-folders Under APPL_TOP (Folder/directory) with below conditions i) the directory names should start with xx..... (like xxau,xxcfi,xxcca...etc) and exclude the directory... (11 Replies)
Discussion started by: gagan4599
11 Replies

3. Shell Programming and Scripting

Find regex

Hi There, Can anybody help me out for searching this regular expression? xxxxx.yyy.zzzz.From-ABCD.To-XYZ.xxxxxx I would like the ID1 and ID2 (knowing which one is Id1 and id2) .From-<ID1>. and .To-<ID2>. Thanks in advance!! Regards, Bhaskar (4 Replies)
Discussion started by: bhaskar_m
4 Replies

4. Shell Programming and Scripting

find regex and remove #

hi , how do i remove # from a line where i found regex.. don't need to remove all the line.. only remove comment.. (3 Replies)
Discussion started by: Poki
3 Replies

5. Shell Programming and Scripting

regex help with 'find'

How to do alternation using regular expressions in the 'find' command? Like say you want to find all files that do not match the names specifically "this" or "that" within a directory using regular expressions? (10 Replies)
Discussion started by: stevensw
10 Replies

6. UNIX for Dummies Questions & Answers

Using regex in find command

I don't understand why the following simple command is not working: find assign{1,2}Variations don't work, either: find assign+ find assign? ls assignAll I am trying to do is make an alias for running a C++ program of the name assign# or assign##. But the regular expressions aren't working. @_@... (27 Replies)
Discussion started by: Zucriy Amsuna
27 Replies

7. Shell Programming and Scripting

find -regex option

I'm trying to use regular expression arguments as variables. I have to surround the regular expression with double quotes or else it automatically expands that regular expression to whatever is in that directory. Unfortunately when I run 'find' it further surrounds the double quotes with single... (6 Replies)
Discussion started by: stevensw
6 Replies

8. UNIX for Dummies Questions & Answers

Using grep command to find the pattern of text in all directories and sub-directories.

Hi all, Using grep command, i want to find the pattern of text in all directories and sub-directories. e.g: if i want to search for a pattern named "parmeter", i used the command grep -i "param" ../* is this correct? (1 Reply)
Discussion started by: vinothrajan55
1 Replies

9. Shell Programming and Scripting

what's wrong with my regex using find

#ls json-* json-lexer.c json-lexer.h json-parser.c json-parser.h json-streamer.c json-streamer.h #find . -regex '^(json-)+.' return nothing (3 Replies)
Discussion started by: yanglei_fage
3 Replies

10. UNIX for Dummies Questions & Answers

Find command and regex

Hi All, We have to copy some files from a source directory to a destination directory. We only have to copy the file if the filename is in a list of values. We can use find command: find . -type f -name '*_111.txt' -o -name '*_115.txt' ... -exec cp {} /tmp \; But the list contains... (3 Replies)
Discussion started by: bartleby
3 Replies
SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
All times are GMT -4. The time now is 03:10 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy