I been trying to figure out how to use element of array as a replacement pattern. This works as I expected:
So why does this not?
How do I access the element of array tmp[<captured_string>]?
Thank you.
I have a function
awkvarrep() {
awk -F'|' '$1~/$1/{printf "%-10s %-30s %-15s %-30s %-15s\n", $2,$3,$4,$5,$6}' testfile
}
I'm calling it by this
VARREP=XYZ
awkvarrep $VARREP
since i'm passing $VARREP to the awkvarrep() function I want to use this with $1 but it dosen't seem to be... (5 Replies)
Hello,
I have a variable that displays the following results from a JVM....
1602100K->1578435K
I would like to collect the value of 1578435 which is the value after a garbage collection. I've tried the following command but it looks like I can't get the > to work. Any suggestions as... (4 Replies)
Hi all
I want to do a simple substitution in awk but I am getting unexpected output. My function accepts a time and then prints out a validation message if the time is valid. However some times may include a : and i want to strip this out if it exists before i get to the validation. I have shown... (4 Replies)
Hi,
Can some one please explain the following line please throw some light on the ones marked in red
awk '{print $9}' ${FTP_LOG} | awk -v start=${START_DATE} 'BEGIN { FS = "." } { old_line1=$0; gsub(/\-/,""); if ( $3 >= start ) print old_line1 }' | awk -v end=${END_DATE} 'BEGIN { FS="." } {... (3 Replies)
I want to replace comma with space and "*646#" with space.
I am using the following code:
nawk -F"|" '{gsub(","," ",$3); gsub(/\*646\#/"," ",$3);print}' OFS="|" file
I am getting following error:
Help is appreciated (5 Replies)
Would really appreciate it if someone could point out my mistake in this line of code, i've been staring blankly at it trying everything i can think of some time now and coming up with nothing.
#!/bin/bash
echo "Enter Username"
read Username
awk -F: -v var=${Username} '/^var:/... (9 Replies)
Hi, I want to print the first column with original value and without any double quotes
The output should look like
<original column>|<column without quotes>
$ cat a.txt
"20121023","19301229712","100397"
"20121023","19361629712","100778"
"20121030A","19361630412","100838"... (3 Replies)
Hello, I had some difficulty to understand the gsub function and maybe the regex in this script to remove all the punctuations:
awk 'gsub(//, " ", $0)' text.txtFile text.txt:
This is a test for gsub
I typed this random text file
which contains punctuation like ,.;!'"?/\ etc.
The script... (6 Replies)
Hello,
I have searched but failed to find what exactly im looking for,
I need to eliminate first "." in a output so i can use something like the following
echo "./abc/20141127" | nawk '{gsub("^.","");print}'
what i want is to use gsub result later on, how could i achieve it?
Let say... (4 Replies)
Discussion started by: EAGL€
4 Replies
LEARN ABOUT PHP
ereg_replace
EREG_REPLACE(3) 1 EREG_REPLACE(3)ereg_replace - Replace regular expressionSYNOPSIS
string ereg_replace (string $pattern, string $replacement, string $string)
DESCRIPTION
This function scans $string for matches to $pattern, then replaces the matched text with $replacement.
Warning
This function has been DEPRECATED as of PHP 5.3.0. Relying on this feature is highly discouraged.
PARAMETERS
o $pattern
- A POSIX extended regular expression.
o $replacement
- If $pattern contains parenthesized substrings, $replacement may contain substrings of the form digit, which will be replaced
by the text matching the digit'th parenthesized substring; will produce the entire contents of string. Up to nine substrings
may be used. Parentheses may be nested, in which case they are counted by the opening parenthesis.
o $string
- The input string.
RETURN VALUES
The modified string is returned. If no matches are found in $string, then it will be returned unchanged.
EXAMPLES
For example, the following code snippet prints "This was a test" three times:
Example #1
ereg_replace(3) example
<?php
$string = "This is a test";
echo str_replace(" is", " was", $string);
echo ereg_replace("( )is", "\1was", $string);
echo ereg_replace("(( )is)", "\2was", $string);
?>
One thing to take note of is that if you use an integer value as the $replacement parameter, you may not get the results you expect. This
is because ereg_replace(3) will interpret the number as the ordinal value of a character, and apply that. For instance:
Example #2
ereg_replace(3) example
<?php
/* This will not work as expected. */
$num = 4;
$string = "This string has four words.";
$string = ereg_replace('four', $num, $string);
echo $string; /* Output: 'This string has words.' */
/* This will work. */
$num = '4';
$string = "This string has four words.";
$string = ereg_replace('four', $num, $string);
echo $string; /* Output: 'This string has 4 words.' */
?>
Example #3
Replace URLs with links
<?php
$text = ereg_replace("[[:alpha:]]+://[^<>[:space:]]+[[:alnum:]/]",
'<a href="\0">\0</a>', $text);
?>
NOTES
Note
As of PHP 5.3.0, the regex extension is deprecated in favor of the PCRE extension. Calling this function will issue an E_DEPRECATED
notice. See the list of differences for help on converting to PCRE.
Tip
ereg_replace(3) is deprecated as of PHP 5.3.0. preg_replace(3) is the suggested alternative to this function.
SEE ALSO ereg(3), eregi(3), eregi_replace(3), str_replace(3), preg_replace(3), quotemeta(3).
PHP Documentation Group EREG_REPLACE(3)