Sponsored Content
Top Forums Shell Programming and Scripting Make pwd print escape character Post 302511874 by Chubler_XL on Thursday 7th of April 2011 08:28:35 PM
Old 04-07-2011
How about:
Code:
cd ()
{
    cd "$@"
    echo ${PWD// /\\ }
}

I used "$@" instead of "$1" just in case you wanted to use -L or -P with cd
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Escape character in vi?

I want to replace a string which contains "/" in vi but what is the escape character for forward slash? e.g. I have a text file with the contents below and I want to replace "/Top/Sub/Sub1" with "ABC". /Top/Sub/Sub1 The replace command I am using is ... (4 Replies)
Discussion started by: stevefox
4 Replies

2. Shell Programming and Scripting

Escape character

Hi , I want to change space to ' in my script. I tried doing this, sed 's/ /\'/g' filename but i could not get it. can some one help me please. Thanks, Deepak (4 Replies)
Discussion started by: deepakpv
4 Replies

3. Shell Programming and Scripting

Escape character - sed

Hi All, How do i write in sed for the 6th and 7th field of etc/passwd file as it involves "/" character? Does mine below is correct? It's incomplete script as i need help with syntax as i always getting may errors :( Example of etc/passwd file: blah:x:1055:600:blah... (6 Replies)
Discussion started by: c00kie88
6 Replies

4. Shell Programming and Scripting

Escape character in sed

Hello experts I am trying to write a shell script which will add ' ' to a unix variable and then pass it to oracle for inserting to a table. I am running the script as root and I have to do a su -c . The problem is the character ' is not recognised inside sed even after adding escape... (1 Reply)
Discussion started by: pvedaa
1 Replies

5. Shell Programming and Scripting

perl how to escape (|) character

my @array; my $sepa = "|"; print $sepa; open FH, "<100_20091023_2.txt"; while(<FH>){ push @array, split(/\$sepa/, $_); print "@array\n\n"; } I am not able split the line which have | separated (1 Reply)
Discussion started by: pritish.sas
1 Replies

6. Shell Programming and Scripting

awk escape character

ll|awk '{print "INSERT INTO SCHEMA.TABLE_NAME VALUES (`"$9 "`,"$5");" }' INSERT INTO SCHEMA.TABLE_NAME VALUES (``,); INSERT INTO SCHEMA.TABLE_NAME VALUES (`TABLE_PARTITION_Y2010M03D06.dmp`,7923328); INSERT INTO SCHEMA.TABLE_NAME VALUES (`TABLE_PARTITION_Y2010M03D06.log`,1389); But I want ' in... (2 Replies)
Discussion started by: faruque.ahmed
2 Replies

7. Shell Programming and Scripting

replace \ (escape character)

All , i have input line as below . abc\ , ewioweioi \, and want the output as below removing the "\" abc , ewioweioi , could anyone help me out (2 Replies)
Discussion started by: expert
2 Replies

8. Shell Programming and Scripting

escape character not working

I need to change a pattern with single quotes # echo "serversignature: 'On'" serversignature: 'On' I did # echo "serversignature: 'On'" | sed 's/.*serversignature.*/serversignature: 'Off'/' serversignature: Off The output I need is with single quotes. But its swallowing it. ... (2 Replies)
Discussion started by: anilcliff
2 Replies

9. Shell Programming and Scripting

ksh escape a character

friends, I have a situation where i am using a $RANDOM function along with the filename, I want this to be escaped by the OS in the first assignment (works as expected) and executed in the second assignment (does not execute $RANDOM) filename1=filename1_\$RANDOM echo $filename1... (3 Replies)
Discussion started by: Balaji M
3 Replies

10. Shell Programming and Scripting

Function to add escape character before specified character

Hi , I am looking for a function which will do the following. 1. I have a variable which will hold few special chracter like SPECIAL_CHARS="& ;"2. I have an escape character. ESCAPE_CHAR="\"3. Now when I passed some string in the function it will return the same string but now it will... (8 Replies)
Discussion started by: Anupam_Halder
8 Replies
SQLSRV_CONNECT(3)														 SQLSRV_CONNECT(3)

sqlsrv_connect - Opens a connection to a Microsoft SQL Server database

SYNOPSIS
resource sqlsrv_connect (string $serverName, [array $connectionInfo]) DESCRIPTION
Opens a connection to a Microsoft SQL Server database. By default, the connection is attempted using Windows Authentication. To connect using SQL Server Authentication, include "UID" and "PWD" in the connection options array. PARAMETERS
o $serverName - The name of the server to which a connection is established. To connect to a specific instance, follow the server name with a forward slash and the instance name (e.g. serverNamesqlexpress). o $connectionInfo - An associative array that specifies options for connecting to the server. If values for the UID and PWD keys are not specified, the connection will be attempted using Windows Authentication. For a complete list of supported keys, see SQLSRV Connection Options. RETURN VALUES
A connection resource. If a connection cannot be successfully opened, FALSE is returned. EXAMPLES
Example #1 Connect using Windows Authentication. <?php $serverName = "serverNamesqlexpress"; //serverNameinstanceName // Since UID and PWD are not specified in the $connectionInfo array, // The connection will be attempted using Windows Authentication. $connectionInfo = array( "Database"=>"dbName"); $conn = sqlsrv_connect( $serverName, $connectionInfo); if( $conn ) { echo "Connection established.<br />"; }else{ echo "Connection could not be established.<br />"; die( print_r( sqlsrv_errors(), true)); } ?> Example #2 Connect by specifying a user name and password. <?php $serverName = "serverNamesqlexpress"; //serverNameinstanceName $connectionInfo = array( "Database"=>"dbName", "UID"=>"userName", "PWD"=>"password"); $conn = sqlsrv_connect( $serverName, $connectionInfo); if( $conn ) { echo "Connection established.<br />"; }else{ echo "Connection could not be established.<br />"; die( print_r( sqlsrv_errors(), true)); } ?> Example #3 Connect on a specifed port. <?php $serverName = "serverNamesqlexpress, 1542"; //serverNameinstanceName, portNumber (default is 1433) $connectionInfo = array( "Database"=>"dbName", "UID"=>"userName", "PWD"=>"password"); $conn = sqlsrv_connect( $serverName, $connectionInfo); if( $conn ) { echo "Connection established.<br />"; }else{ echo "Connection could not be established.<br />"; die( print_r( sqlsrv_errors(), true)); } ?> NOTES
By default, the sqlsrv_connect(3) uses connection pooling to improve connection performance. To turn off connection pooling (i.e. force a new connection on each call), set the "ConnectionPooling" option in the $connectionOptions array to 0 (or FALSE). For more information, see SQLSRV Connection Pooling. The SQLSRV extension does not have a dedicated function for changing which database is connected to. The target database is specified in the $connectionOptions array that is passed to sqlsrv_connect. To change the database on an open connection, execute the following query "USE dbName" (e.g. sqlsrv_query($conn, "USE dbName")). SEE ALSO
sqlsrv_close(3), sqlsrv_errors(3), sqlsrv_query(3). PHP Documentation Group SQLSRV_CONNECT(3)
All times are GMT -4. The time now is 01:21 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy