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Top Forums Shell Programming and Scripting Cron job initiating ssh AND sudo (from user, not root) Post 302511701 by eh3civic on Thursday 7th of April 2011 01:40:23 PM
Old 04-07-2011
Quote:
Originally Posted by kitykity
I know you've said you added the absolute path... but in the command above, I don't see an absolute path to sudo...
Oh sorry, I edited out the paths on my post to more easily present the coding. I haven't tried the solution on that page yet because it requires modifying REQUIRESTTY, which I get around by using the -t option in ssh. I have security worries with commenting out REQUIRESTTY, but if no other options come up, I suppose that is what will have to happen.

---------- Post updated at 01:40 PM ---------- Previous update was at 10:48 AM ----------

I did try the individual version of what was described about, but now I have satisfied my test script, but I still have issues with my "real" script. Just in case, I'll post the temporary solution for now, which was just to add in a user based requiretty in /etc/sudoers

Default:john !requiretty

I'll post my supersolution, once I come across it.
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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