04-06-2011
wouldnt this work, since strings are pointers?
buf=buf+5;
and whats the difference between declaring a string like
char *buf;
and
char buf[10];
arent they both pointers? But in some cases the way i declare it makes a difference through...
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LEARN ABOUT REDHAT
ne_buffer_concat
NE_BUFFER_APPEND(3) neon API reference NE_BUFFER_APPEND(3)
NAME
ne_buffer_append, ne_buffer_zappend, ne_buffer_concat - append data to a string buffer
SYNOPSIS
#include <ne_string.h>
void ne_buffer_append (ne_buffer *buf, const char *string, size_t len);
void ne_buffer_zappend (ne_buffer *buf, const char *string);
void ne_buffer_concat (ne_buffer *buf, const char *str, ...);
DESCRIPTION
The ne_buffer_append and ne_buffer_zappend functions append a string to the end of a buffer; extending the buffer as necessary. The len
passed to ne_buffer_append specifies the length of the string to append; there must be no NUL terminator in the first len bytes of the
string. ne_buffer_zappend must be passed a NUL-terminated string.
The ne_buffer_concat function takes a variable-length argument list following str; each argument must be a char * pointer to a NUL-termi-
nated string. A NULL pointer must be given as the last argument to mark the end of the list. The strings (including str) are appended to
the buffer in the order given. None of the strings passed to ne_buffer_concat are modified.
EXAMPLES
The following code will output "Hello, world. And goodbye.".
ne_buffer *buf = ne_buffer_create();
ne_buffer_zappend(buf, "Hello");
ne_buffer_concat(buf, ", world. ", "And ", "goodbye.", NULL);
puts(buf->data);
ne_buffer_destroy(buf);
SEE ALSO
ne_buffer(3), ne_buffer_create(3), ne_buffer_destroy(3)
AUTHOR
Joe Orton <neon@webdav.org>.
neon 0.23.5 8 October 2002 NE_BUFFER_APPEND(3)