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Top Forums Shell Programming and Scripting Converting date DD MM YYYY to DD MON YYYY Post 302510975 by Adamm on Tuesday 5th of April 2011 11:40:10 AM
Old 04-05-2011
Dahu: thank you, that was helpful.

Is there a way to do it the other way round as well? That means from i.e. 26 Mar 2011 get 20110326?

Tried the following, but not much success. Does date really only accept date in YYYYMMDD format?
Code:
date +'%d %m %Y %H:%M:%S' -d "2011Mar26"
date +'%d %m %Y %H:%M:%S' -d "26 Mar 2011"


Last edited by Scott; 04-05-2011 at 01:38 PM..
 

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DATETIMEIMMUTABLE.FORMAT(3)						 1					       DATETIMEIMMUTABLE.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTimeImmutable.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIMEIMMUTABLE.FORMAT(3)
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