I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10)
To extract the dates, I am using shell substrings, i.e.:
Code:
read line
year=${line:8:4}
month=${line:5:2}
day=${line:2:2}
hour=${line:13:2}
min=${line:16:2}
sec=${line:19:2}
echo "$year$month$day$hour$min$sec" # prints something like 20110325161610 (I use this numeric value to compare it agains reference date, i.e. date when this script ran last time)
if [ "$year$month$day$hour$min$sec" -gt "$lastlog" ]
then
# output date in DD MON FORMAT... how?
fi
Of course I can do a routine like: if mon = 01 then mon = 'JAN', if mon = 02 then mon = 'FEB'... But I guess there must be a nicer solution to this. Maybe solution that will take into account also LANG setting (not a requirement, but would like to have it).
Maybe date function can be used for that, but I did not figure out how to pass the -d parameter (what format should it be in?). Did not find much in FAQ: Date Arithmetics either
I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix
my script will generate text file which have two fields
one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
I have a file which has 100k+ records like this
abc,05-JUN-1974,def,lkj,aaa
def,11-SEP-1975,ghj,dis,dea
I want to convert ex 05-JUN-1974 to 06/05/1974
Please help me with awk script to convert the whole file into MM-DD-YYYY
Thank you! (2 Replies)
Hi all
I have some pipe-separated data in the form:
5/12/2008 00:00:00|31/1/2009 00:00:00|SOMESTUFF|OTHERSTUFF
12/31/2008 00:00:00|15/1/2009 00:00:00|MORESTUFF|REMAININGSTUFF
1/1/1023 00:00:00|16/5/2047 00:00:00|THEREST|YETMORE
I need to zero-pad the single-digit days and months, using... (3 Replies)
Hi All,
I am learning PERL for one of the projects, and in one of these scripts, I read a flat text file and print in the terminal.
The problem is, the text file has a date field. The format is yyyymmdd. I need to display this as dd-mon-yyyy.
Any ideas to do this? Thanks a lot for the... (9 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Hi I have a problem with Date format in my code.
1st I am trying to convert today's date to yesterday's using
YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'`
And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
I've seen a lot of posts on this and have tried the following:
echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";'
But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY.
I am using bash and don't know... (4 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)
Discussion started by: Roozo
3 Replies
LEARN ABOUT DEBIAN
html::formhandler::field::date
HTML::FormHandler::Field::Date(3pm) User Contributed Perl Documentation HTML::FormHandler::Field::Date(3pm)NAME
HTML::FormHandler::Field::Date - a date field with formats
VERSION
version 0.40013
SUMMARY
This field may be used with the jQuery Datepicker plugin.
You can specify the format for the date using jQuery formatDate strings or DateTime strftime formats. (Default format is format =>
'%Y-%m-%d'.)
d - "%e" - day of month (no leading zero)
dd - "%d" - day of month (two digit)
o - "%{day_of_year}" - day of the year (no leading zeros)
oo - "%j" - day of the year (three digit)
D - "%a" - day name short
DD - "%A" - day name long
m - "%{day_of_month" - month of year (no leading zero)
mm - "%m" - month of year (two digit) "%m"
M - "%b" - month name short
MM - "%B" - month name long
y - "%y" - year (two digit)
yy - "%Y" - year (four digit)
@ - "%s" - Unix timestamp (ms since 01/01/1970)
For example:
has_field 'start_date' => ( type => 'Date', format => "dd/mm/y" );
or
has_field 'start_date' => ( type => 'Date', format => "%d/%m/%y" );
You can also set 'date_end' and 'date_start' attributes for validation of the date range. Use iso_8601 formats for these dates ("yyyy-mm-
dd");
has_field 'start_date' => ( type => 'Date', date_start => "2009-12-25" );
Customize error messages 'date_early' and 'date_late':
has_field 'start_date' => ( type => 'Date,
messages => { date_early => 'Pick a later date',
date_late => 'Pick an earlier date', } );
If form has 'is_html5' flag active it will render <input type="date" ... /> instead of type="text"
AUTHOR
FormHandler Contributors - see HTML::FormHandler
COPYRIGHT AND LICENSE
This software is copyright (c) 2012 by Gerda Shank.
This is free software; you can redistribute it and/or modify it under the same terms as the Perl 5 programming language system itself.
perl v5.14.2 2012-06-25 HTML::FormHandler::Field::Date(3pm)
04-05-2011
