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Top Forums Shell Programming and Scripting passing arguments to external script Post 302510572 by Corona688 on Monday 4th of April 2011 11:31:37 AM
Old 04-04-2011
What happens when you run the script manually with those names?

There may be other reasons than filenames that your script is failing.

Also, what are the exact contents of the file_paths variable? Not made up, not paraphrased.

Last edited by Corona688; 04-04-2011 at 12:37 PM..
 

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MAKESH(1)						      General Commands Manual							 MAKESH(1)

NAME
makeSH - a .SH script maker SYNOPSIS
makeSH files DESCRIPTION
MakeSH examines one or more scripts and produces a .SH file that, when run under sh, will produce the original script. The .SH script so produced has two sections containing code destined for the output. The first section has variable substitutions performed on it (taking values from config.sh), while the second section does not. MakeSH does not know which variables you want to have substituted, so it puts the whole script into the second section. It's up to you to insert any variable substitutions in the first section for any values you want from config.sh. You should run makeSH from within your top-level directory and use the relative path to the file as an argument, so that the "Extracting ..." line printed while running the produced .SH file later on will give that same path. AUTHOR
Larry Wall <lwall@netlabs.com> SEE ALSO
pat(1), metaconfig(1), makedist(1). BUGS
It could assume that variables from metaconfig's Glossary need to be initialized in the first section, but I'm too lazy to make it do that. LOCAL MAKESH(1)
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