but i have another issue, i need to search in first column for numbers greater than 3000 then searching in the second column of the output for A or N then searching in the third column of the output for value starts with 2xx
I am using awk and it stops when it encounter line greater then 3000 character. Is there any command which will help me remove line greater then 3000 characters. (10 Replies)
Could someone tell me how to perform calculations using numbers greater than 2150000000 in Korn Shell? When I tried to do it it gave me the wrong answer.
e.g. I have a ksh file with the contents below:
---------------------------------
#!/bin/ksh
SUM=`expr 2150000000 + 2`
PRODUCT=`expr... (3 Replies)
I have some ASCII files containing numerous numbers. What I'd like to do is replace all numbers greater than 0 with 1.
Examples of the numbers include: - 000011 and 000042
Thanks (4 Replies)
My Script:
#!/bin/sh
date=`date +%y%m%d -d"1 day ago"`
in_dir=/vis/logfiles/to_solmis
cp `grep -il ST~856~ $inbound_dir/*$date*` /vis/sumit/in_ASN/
for i in /vis/sumit/in_ASN/*
do
mkdir -p /vis/sumit/inboundasns.$date
cp `echo $i`... (1 Reply)
Hi, as the title states i need to find a way to search a column for values great than 1000, and if it is, then delete that row.
An example
1 7.021 6.967 116.019 4 U 6.980E+07 0.000E+00 e 0 0 0 0
2 8.292 7.908 118.063 3 U 1.440E+07 0.000E+00 e 0 821 814 ... (3 Replies)
Hi, I need to write a script that will read each line of a CSV file, look for values greater than x seconds and email an alert.
For the first part, I have one CSV per day, each line in the CSV has comma separated values. There are a total of 8 fields per line separated by commas. 6th and 7th... (3 Replies)
I have a file with multiple fields, example below
File 1:
Field 1|Field 2|Field 3|Field 4|Field 5|Field 6|Field 7|100
Field 1|Field 2|Field 3|Field 4|Field 5|Field 6|Field 7|101
Field 1|Field 2|Field 3|Field 4|Field 5|Field 6|Field 7|102
Field 1|Field 2|Field 3|Field 4|Field 5|Field... (4 Replies)
I'm trying to grep lines where the digits at the end of each line are greater than digits. Tried this but it will only allow me to specify 2 digits. Any ideas would greatly be appreciated. grep -i '\<\{3,4,5\}\>' file
---------- Post updated at 05:58 PM ---------- Previous update was at 05:41... (1 Reply)
How do I find the files greater than or equal to a given size using find command.
find ./ -size +0k --> Lists files greater than 0K
find ./ -size 0k --> Lists the file size equal to 0K.
I have other conditions to check, hence using find command.
Thanks in advance. (4 Replies)
This helped get me started.
https://www.unix.com/unix-for-dummies-questions-and-answers/157026-need-command-search-numbers-greater-than-3000-a.html
This is the command I am using. I am trying to find numbers greater than 70 in column 5. I do not know if it is getting confused because there... (6 Replies)
Discussion started by: cokedude
6 Replies
LEARN ABOUT PHP
db2_field_scale
DB2_FIELD_SCALE(3) 1 DB2_FIELD_SCALE(3)db2_field_scale - Returns the scale of the indicated column in a result setSYNOPSIS
int db2_field_scale (resource $stmt, mixed $column)
DESCRIPTION
Returns the scale of the indicated column in a result set.
PARAMETERS
o $stmt
- Specifies a statement resource containing a result set.
o $column
- Specifies the column in the result set. This can either be an integer representing the 0-indexed position of the column, or a
string containing the name of the column.
RETURN VALUES
Returns an integer containing the scale of the specified column. If the specified column does not exist in the result set,
db2_field_scale(3) returns FALSE.
SEE ALSO db2_field_display_size(3), db2_field_name(3), db2_field_num(3), db2_field_precision(3), db2_field_type(3), db2_field_width(3).
PHP Documentation Group DB2_FIELD_SCALE(3)