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Full Discussion: Printing pointer address
Top Forums UNIX for Dummies Questions & Answers Printing pointer address Post 302508967 by perleo on Tuesday 29th of March 2011 01:27:33 PM
Old 03-29-2011
Quote:
Originally Posted by Corona688
What happens when you compile and run this code:

Code:
#include <stdio.h>

int main(void)
{
        printf("pointer:  %p\n", NULL);
}

prints out..

pointer: 0x0

however, if I try to print out a pointer address in the kernel code and compile, it returns that %p is looking for a void.
 

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PAPI_strerror(3)						       PAPI							  PAPI_strerror(3)

NAME
PAPI_strerror - Returns a string describing the PAPI error code. SYNOPSIS
Detailed Description C Interface: #include <papi.h> char * PAPI_strerror( int errorCode ); Parameters: code -- the error code to interpret Return values: *error -- a pointer to the error string. NULL -- the input error code to PAPI_strerror() is invalid. PAPI_strerror() returns a pointer to the error message corresponding to the error code code. If the call fails the function returns the NULL pointer. This function is not implemented in Fortran. Example: * int ret; * int EventSet = PAPI_NULL; * int native = 0x0; * char error_str[PAPI_MAX_STR_LEN]; * * ret = PAPI_create_eventset(&EventSet); * if (ret != PAPI_OK) * { * fprintf(stderr, "PAPI error %d: %s0, ret, PAPI_strerror(retval)); * exit(1); * } * // Add Total Instructions Executed to our EventSet * ret = PAPI_add_event(EventSet, PAPI_TOT_INS); * if (ret != PAPI_OK) * { * PAPI_perror( "PAPI_add_event"); * fprintf(stderr,"PAPI_error %d: %s0, ret, error_str); * exit(1); * } * // Start counting * ret = PAPI_start(EventSet); * if (ret != PAPI_OK) handle_error(ret); * See Also: PAPI_perror PAPI_set_opt PAPI_get_opt PAPI_shutdown PAPI_set_debug Author Generated automatically by Doxygen for PAPI from the source code. Version 5.2.0.0 Tue Jun 17 2014 PAPI_strerror(3)
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