Sponsored Content
Top Forums Shell Programming and Scripting script to ignore the user from list of users Post 302508074 by Chubler_XL on Friday 25th of March 2011 03:36:03 PM
Old 03-25-2011
Put exclude users in a file (1 per line) and use
Code:
grep -Fvf exclude_users.txt  userlist.txt

 

9 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

su - user... how to find out the list of users and their passwords..

hi, to do a su - user, we need to know what are the users... so in unix 1) which file to see the list of users, passwords? (2 Replies)
Discussion started by: yls177
2 Replies

2. AIX

Script allows user to kill other users: I'd like to know HOW...

Hello list, Have a problem that's highlighting gaps in my knowledge; can you assist? We have a script that's tacked onto our trading application which allows branch managers etc. to kill off the sessions of other users at their branch. A menu option in the application spawns a shell running... (8 Replies)
Discussion started by: alexop
8 Replies

3. UNIX for Dummies Questions & Answers

User Name and Password List/adding and removing users.

Hello everyone and let me start off by thanking anyone who can help with this. I work for a company that uses Unix as one of their servers. I'm not at all familar with Unix beyond logging after I restart the server:rolleyes: I'm looking for some command that will bring me up a list of current... (3 Replies)
Discussion started by: disgracedsaint
3 Replies

4. Shell Programming and Scripting

IF $USER is not in this list of users, then do this

I need to add to a BASH script if ${USER} is not in a list of users (smitha, brownd, adamsp) then do something... what is the best shortest way to accomplish an if statement with a list like this? Also the list of users should be in the script, not an external file. Thanks! (5 Replies)
Discussion started by: glev2005
5 Replies

5. Shell Programming and Scripting

Script to list users and their last login?

hi all, I'm trying to write a script to create a file with a list of all users, their gid, gecos field and their last login time e.g. fairly new to scripting, this is what I've got so far #!/bin/sh( userlist= cat /etc/passwd | awk -F: '{print $1," ",$4," ",$5}' for name in $userlist... (3 Replies)
Discussion started by: tanngo
3 Replies

6. Shell Programming and Scripting

Script to list primary group of users

Dear All I am facing a problem with my script. I have to found the primary group of users . So first I selected all the groups and users register from a specific user : ONE Then I am making a file with all groups attached to the user : ONE Then I am making a file with all... (8 Replies)
Discussion started by: Aswex
8 Replies

7. UNIX for Advanced & Expert Users

Need A Script To List All Failed Log In Users

I need to list all the failed log in users as part of audit report. How can I do so in Linux to find all the audit log records and then upload to a table for future reference. I am using oracle 10g on Linux. Hope I will get a quick response from the experts. Thanks in advance for the tips. (3 Replies)
Discussion started by: oraQ
3 Replies

8. Shell Programming and Scripting

help to create script for added date to list users

hi my friends im asking for the possibility to creat a script in ubuntu for added date to list users for doing this : - search in debug connected user of all connected users - if a new user is connect for the first time to my server the script record the date of the connection and added it... (1 Reply)
Discussion started by: amzioujda
1 Replies

9. Shell Programming and Scripting

Shell Script to ignore # and take corresponding user and group

Hi, I have a following file: role.IMPACT_USER.user=admin role.IMPACT_USER.user=dd12345 role.IMPACT_USER.user=ss76767 #role.IMPACT_USER.user=root #role.IMPACT_USER.group=System role.IMPACT_USER.group=ImpactUser #Description: Allow users to login in to Impact, start and stop service... (5 Replies)
Discussion started by: dbashyam
5 Replies
pam_ldap(8)						      System Manager's Manual						       pam_ldap(8)

NAME
pam_ldap - PAM module for LDAP-based authentication SYNOPSIS
pam_ldap.so [...] DESCRIPTION
This is a PAM module that uses an LDAP server to verify user access rights and credentials. OPTIONS
use_first_pass Specifies that the PAM module should use the first password provided in the authentication stack and not prompt the user for a pass- word. try_first_pass Specifies that the PAM module should use the first password provided in the authentication stack and if that fails prompt the user for a password. nullok Specifying this option allows users to log in with a blank password. Normally logins without a password are denied. ignore_unknown_user Specifies that the PAM module should return PAM_IGNORE for users that are not present in the LDAP directory. This causes the PAM framework to ignore this module. ignore_authinfo_unavail Specifies that the PAM module should return PAM_IGNORE if it cannot contact the LDAP server. This causes the PAM framework to ig- nore this module. no_warn Specifies that warning messages should not be propagated to the PAM application. use_authtok This causes the PAM module to use the earlier provided password when changing the password. The module will not prompt the user for a new password (it is analogous to use_first_pass). debug This option causes the PAM module to log debugging information to syslog(3). minimum_uid=UID This option causes the PAM module to ignore the user if the user id is lower than the specified value. This can be used to bypass LDAP checks for system users (e.g. by setting it to 1000). MODULE SERVICES PROVIDED
All services are provided by this module but currently sessions changes are not implemented in the nslcd daemon. FILES
/etc/pam.conf the main PAM configuration file /etc/nslcd.conf The configuration file for the nslcd daemon (see nslcd.conf(5)) SEE ALSO
pam.conf(5), nslcd(8), nslcd.conf(5) AUTHOR
This manual was written by Arthur de Jong <arthur@arthurdejong.org>. Version 0.8.10 Jun 2012 pam_ldap(8)
All times are GMT -4. The time now is 01:15 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy