Hi there,
I've an input file1 as follows:
1001
1002
1003
1004
1005
I would like to have an output file2 as follows:
Numbers are 1001/ 1002/ 1003/ 1004/ 1005/
Any help is appreciated. (2 Replies)
I have . dat file which contains data in a specific format:
0 3 892 921 342
1 3 921 342 543
2 4 817 562 718 765
3 3 819 562 717 761
i need to compare each field in a row with another field of the same column but different row and cont the... (8 Replies)
Hi,
I am new to UNIX. Can some one help me to solve the below.
I have a requirement to to identify the specific fields in row and also some part of the field.
In my file I have a record as
sundra;10.44.48.65;10thstreet TCP packet out of state: First packet isn't SYN;telno:... (3 Replies)
Hi all,
I require to convert julian date to normal calander date in unix
for eg julian date=122
now i want corresponding calander date
----------------------------------------
gr8 if give very small command/script
and please explain the steps as well(imp)
Thanks
... (3 Replies)
Hello gurus,
I am hoping someone can help me with the required code/script to make this work. I have the following file with records starting at line 4:
NETW~US60~000000000013220694~002~~IT~USD~2.24~20110201~99991231~01~01~20101104~... (4 Replies)
I have a file containing rows with the following format.
Field1|Field2|Field3|data1:data data2:data data3:"dataA:data dataB:data" data4:data:data (and so on)
I need to format the above row into multiple rows that look like this:
Field1|Field2|Field3|data1|data
... (2 Replies)
Hi experts,
I need to print the first field first then last two fields should come next and then i need to print rest of the fields.
Input :
a1,abc,jsd,fhf,fkk,b1,b2
a2,acb,dfg,ghj,b3,c4
a3,djf,wdjg,fkg,dff,ggk,d4,d5
Expected output:
a1,b1,b2,abc,jsd,fhf,fkk... (6 Replies)
I have a text file with the geneIds separated by space in each line. The number Ids in lines are different.
The file is like:
abc qwe tyu ghj jkl dfg sdf
cvb sdk fgh tyu
uio iop tyu rty eru wer rty iop
asd sdf dfg fgh zxc
I want to format the file like:
abc
qwe
tyu
ghj
jkl
... (7 Replies)
Hi Unix Forum,
I have a relatively easy question i suppose for which, however, until now i could not find a solution.
I am working with a program that will give me an output file similar to the following:
A
1
2
3
4
B
1
2
3
4
C
1 (9 Replies)
I have the following script that will average the last two fields of each row, but im not sure how to include the 3rd field of the following row.
An example of the analysis that I need to perform from the input - (66.61+58.01+54.16)/3
awk '{sum=cnt=0; for (i=13;i<=NF;i++) { sum+=$i; cnt++... (1 Reply)
Discussion started by: ncwxpanther
1 Replies
LEARN ABOUT DEBIAN
mojo::date
Mojo::Date(3pm) User Contributed Perl Documentation Mojo::Date(3pm)NAME
Mojo::Date - HTTP 1.1 date container
SYNOPSIS
use Mojo::Date;
my $date = Mojo::Date->new(784111777);
my $http_date = $date->to_string;
$date->parse('Sun, 06 Nov 1994 08:49:37 GMT');
my $epoch = $date->epoch;
DESCRIPTION
Mojo::Date implements HTTP 1.1 date and time functions according to RFC 2616.
Sun, 06 Nov 1994 08:49:37 GMT ; RFC 822, updated by RFC 1123
Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
Sun Nov 6 08:49:37 1994 ; ANSI C's asctime() format
ATTRIBUTES
Mojo::Date implements the following attributes.
"epoch"
my $epoch = $date->epoch;
$date = $date->epoch(784111777);
Epoch seconds.
METHODS
Mojo::Date inherits all methods from Mojo::Base and implements the following new ones.
"new"
my $date = Mojo::Date->new;
my $date = Mojo::Date->new($string);
Construct a new Mojo::Date object.
"parse"
$date = $date->parse('Sun Nov 6 08:49:37 1994');
Parse date in one of the following formats.
- Epoch format(784111777)
- RFC 822/1123 (Sun, 06 Nov 1994 08:49:37 GMT)
- RFC 850/1036 (Sunday, 06-Nov-94 08:49:37 GMT)
- ANSI C asctime() (Sun Nov 6 08:49:37 1994)
"to_string"
my $string = $date->to_string;
Render date suitable for HTTP 1.1 messages.
SEE ALSO
Mojolicious, Mojolicious::Guides, <http://mojolicio.us>.
perl v5.14.2 2012-09-05 Mojo::Date(3pm)