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Top Forums Shell Programming and Scripting How to filter only the last 'n' lines of a grep output? Post 302505472 by shell_newbie on Thursday 17th of March 2011 04:03:50 AM
Old 03-17-2011
How to filter only the last 'n' lines of a grep output?

I am running a grep query for searching a pattern, and the output is quite huge. I want only the last 200 lines to be displayed, and I am not sure if tail will do the trick (can tail read from std in/out instead of files?).
Please help me out.
 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
All times are GMT -4. The time now is 05:49 PM.
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