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Top Forums Shell Programming and Scripting delete part of file from pattern1 to pattern2 Post 302504356 by jim mcnamara on Monday 14th of March 2011 11:13:44 AM
Old 03-14-2011
Code:
ls /FOLDER/*.txt | 
while read fname
do
    sed '/pattern1/,/pattern2/d' $fname > tmp.tmp
    mv tmp.tmp $fname
done

For your patterns you need to escape (add a leading \ character) to < and > and /
for example:
Code:
</s>  becomes \<\/s\>

 

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ZIP_SOURCE_FILE(3)					     Library Functions Manual						ZIP_SOURCE_FILE(3)

NAME
zip_source_file - create data source from a file LIBRARY
libzip (-lzip) SYNOPSIS
struct zip_source * zip_source_file(struct zip *archive, const char *fname); "zip_uint64_t start" "zip_int64_t len" DESCRIPTION
The function zip_source_file creates a zip source from a file. zip_source_file opens fname and reads len bytes from offset start from it. If len is 0 or -1, the whole file (starting from start ) is used. The fie is opened and read when the data from the source is used, usually by zip_close. RETURN VALUES
Upon successful completion, the created source is returned. Otherwise, NULL is returned and the error code in archive is set to indicate the error. ERRORS
zip_source_file fails if: [ZIP_ER_INVAL] fname, start, or len are invalid. [ZIP_ER_MEMORY] Required memory could not be allocated. [ZIP_ER_OPEN] Opening fname failed. SEE ALSO
libzip(3), zip_add(3), zip_replace(3), zip_source_buffer(3), zip_source_filep(3), zip_source_free(3), zip_source_function(3), zip_source_zip(3) AUTHORS
Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at> NiH August 1, 2008 ZIP_SOURCE_FILE(3)
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