Sponsored Content
Full Discussion: Last sunday of current date
Top Forums Shell Programming and Scripting Last sunday of current date Post 302504242 by Franklin52 on Monday 14th of March 2011 06:04:23 AM
Old 03-14-2011
Assuming you want the last sunday of the current month:
Code:
cal | awk 'NR==1{$1=$1;m=$0}$1{d=$1}END{print d, m}'

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Date - Last Sunday thru Saturday

Hi All, I have to kick off a script on every Monday to get some data from database for last week (Sunday thru Saturday). If its Monday (12/12/2005) Begin date will be Sunday - 12/4/2005 End date will be Saturday - 12/10/2005 The script might not kick off on some Mondays. So my... (2 Replies)
Discussion started by: skymirror
2 Replies

2. UNIX for Dummies Questions & Answers

How to find last sunday (date) using perl?

How to find last sunday (date) using perl? Eg, If i run today (26-Feb-2008 / Tuesday), I should get 24-Feb-2008 (Sunday). Any help? (3 Replies)
Discussion started by: deepakwins
3 Replies

3. Shell Programming and Scripting

recurrence for every sunday for Date::MAnip in perl

Hi, I have a requirement to define all Saturdays/Sundays of every month in a year as holidays. I am making use of Date::Manip package available in perl. I tried writing a recurrence as : 0:1*3:7:0:0:0 --> this relation helps me to define 3rd Sunday of a year as sunday. My requirement is... (1 Reply)
Discussion started by: harpreetanand
1 Replies

4. Shell Programming and Scripting

Date One Week Ago From Given Date, Not From Current Date

Hi all, I've used various scripts in the past to work out the date last week from the current date, however I now have a need to work out the date 1 week from a given date. So for example, if I have a date of the 23rd July 2010, I would like a script that can work out that one week back was... (4 Replies)
Discussion started by: Donkey25
4 Replies

5. UNIX for Dummies Questions & Answers

Delete a row from a file if one column containing a date is greater than the current system date

Hello gurus, I am hoping someone can help me with the required code/script to make this work. I have the following file with records starting at line 4: NETW~US60~000000000013220694~002~~IT~USD~2.24~20110201~99991231~01~01~20101104~... (4 Replies)
Discussion started by: chumsky
4 Replies

6. Shell Programming and Scripting

How to derive the last Sunday's date when Current date value is passed

Hi All, I have a requirement in my project where a batch runs on any day of a week. The input files will land to the server every Sunday. I need to read these files based on the current BUS_DAY (which falls any day of the week). For e.g : if the BUS_DAY is 20120308, we need to derive the... (3 Replies)
Discussion started by: dsfreddie
3 Replies

7. UNIX for Dummies Questions & Answers

Yesterday's Date if it is Sunday

Hi All, Can you please let me know how to get the yesterday's date of the given date if the given date is Sunday? I can't use GNU. I have the code to get the yesterday's date based on the system date. Thanks (5 Replies)
Discussion started by: shash
5 Replies

8. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies

9. Linux

How to calculate the quarter end date according to the current date in shell script?

Hi, My question is how to calculate the quarter end date according to the current date in shell script? (2 Replies)
Discussion started by: Divya_1234
2 Replies

10. UNIX for Beginners Questions & Answers

How to replace a parameter(variable) date value inside a text files daily with current date?

Hello All, we what we call a parameter file (.txt) where my application read dynamic values when the job is triggered, one of such values are below: abc.txt ------------------ line1 line2 line3 $$EDWS_DATE_INSERT=08-27-2019 line4 $$EDWS_PREV_DATE_INSERT=08-26-2019 I am trying to... (1 Reply)
Discussion started by: pradeepp
1 Replies
CAL(1)								   User Commands							    CAL(1)

NAME
cal - display a calendar SYNOPSIS
cal [options] [[[day] month] year] DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed. OPTIONS
-1, --one Display single month output. (This is the default.) -3, --three Display prev/current/next month output. -s, --sunday Display Sunday as the first day of the week. -m, --monday Display Monday as the first day of the week. -j, --julian Display Julian dates (days one-based, numbered from January 1). -y, --year Display a calendar for the current year. -V, --version Display version information and exit. -h, --help Display help screen and exit. PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar for 1989. Two parameters denote the month (1 - 12) and year. Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no parameters are specified, the current month's calendar is displayed. A year starts on Jan 1. The first day of the week is determined by the locale. The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref- ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so the calendar for that month is a bit unusual. HISTORY
A cal command appeared in Version 6 AT&T UNIX. AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/. util-linux June 2011 CAL(1)
All times are GMT -4. The time now is 04:39 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy