I hope that's an example of how not to do something because it doesn't work.
The idea, I think, is to run the ls command to list the current directory, and feed its output into the more program so you can view it page by page. But you can't dump that text into a variable and expect it to work because the shell doesn't evaluate variables that way unless you force it to with eval.
Should I be concerned about the %runocc value be always 100. The CPU is 99% idle all the time and the paging is 0
MyMachine|10/23/2007 00:00:05|1.0|100||
MyMachine|10/23/2007 00:05:04|1.0|100||
MyMachine|10/23/2007 00:10:04|1.0|100||
MyMachine|10/23/2007 00:15:04|1.0|100||... (2 Replies)
Hi guys,
I have no idea on unix but suddenly, my cobol programs calls a unix script that i know nothing about.
can you guys interpret these lines for me?
i know its a print command but I want to actually know how many copies it prints.
qprt -da -P $1 -t '6' -i '6' -l '70' $2
qprt -da... (1 Reply)
Can someone help me out here. I can't get this piece of code to work. i.e. $ALL_EVENTS does not get interpreted in the if brackets. The first part is the code, the second part is the execution of the code. Note: $ALL_EVENTS does equal 2, but there is no value once passed to the if statement. ... (4 Replies)
Hi,
So I am new to Unix, and I need to check the performance of some apps I am running. But I don't know how to interpret the output from TOP.
Could somebody please explain the difference between the different values. And also explain how I can have a process which has a %CPU > 100?
... (7 Replies)
Was wondering if someone could interpret this for me -- I'm not sure what everything means. It's a shell script from my bash book:
cd ()
{
builtin cd "$@"
es=$?
echo "$OLDPWD ->$PWD"
return $es
}
what I don't quite understand is the "$@". I think, if I understand... (6 Replies)
I know $0 is the entire file's contents (at least I think that is what it is!), but what exactly is: $0!~
This was a snippet from a larger line
awk '$0!~/^$/ {print $0}'
This deletes blank lines, but I want to know specifically the $0!~ part... I am guessing /^$/ is regex for blank line...... (5 Replies)
hi All,
i have never used sed in Unix environment, but i have one script which is using this following command:
cat audit_session_rpt_MSP_20140331.lst|sed -n '/Apr 14/!p'| sed -n '/Page/!p'| sed -n '/UserName/!p' |\
egrep -v '^-|^=|^\*'|sed '/^$/d'|sed -e '1,7d'... (1 Reply)
I booted into single user mode with
/usr/sbin/reboot -- -s
but after doing a control -d
my
who -r
shows
run-level 3 Nov 17 14:07 3 0 S
I was expecting it to show run-level S
why is this still in run level 3?
thanks (1 Reply)
Discussion started by: goya
1 Replies
LEARN ABOUT MOJAVE
pwd
PWD(1) BSD General Commands Manual PWD(1)NAME
pwd -- return working directory name
SYNOPSIS
pwd [-L | -P]
DESCRIPTION
The pwd utility writes the absolute pathname of the current working directory to the standard output.
Some shells may provide a builtin pwd command which is similar or identical to this utility. Consult the builtin(1) manual page.
The options are as follows:
-L Display the logical current working directory.
-P Display the physical current working directory (all symbolic links resolved).
If no options are specified, the -L option is assumed.
ENVIRONMENT
Environment variables used by pwd:
PWD Logical current working directory.
EXIT STATUS
The pwd utility exits 0 on success, and >0 if an error occurs.
SEE ALSO builtin(1), cd(1), csh(1), sh(1), getcwd(3)STANDARDS
The pwd utility conforms to IEEE Std 1003.1-2001 (``POSIX.1'').
BUGS
In csh(1) the command dirs is always faster because it is built into that shell. However, it can give a different answer in the rare case
that the current directory or a containing directory was moved after the shell descended into it.
The -L option does not work unless the PWD environment variable is exported by the shell.
BSD April 12, 2003 BSD