Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
This function is given the day, month and year and returns the Julian date. The Julian date is the ordinal day number for that day. For example, 1 Jan is day 1 of any year, 31 Dec is day 365 for any non-leap year and 1 Feb is day 32 for any year. Use your days_in_month() function from the previous problem to calculate the Julian date. Put the code for the function julian_date() in the file julian.c, and the prototype in the file julian.h Write a driver, main(), which asks the user to enter a month, day, year and prints the Julian date. Terminate with EOF. Put the driver in the file driver3.c. You will compile this program with the command:
2. Relevant commands, code, scripts, algorithms:
Other code that relates to it would be the days.h and leap.h
3. The attempts at a solution (include all code and scripts):
for julian.c 4. Complete Name of School (University), City (State), Country, Name of Professor, and Course Number (Link to Course):
University of Hawaii at Manoa, Honolulu (HI), Oahu (Hawaii), Tep Dobry, EE 160
( i can't post any URL for i am new to this forum but type tep dobry in google and the link to the course should be titled with 2011 after the link is connected the information is in its in the homework section)
If you need more info i'll post up more
Thank you for your time
Note: Without school/professor/course information, you will be banned if you post here! You must complete the entire template (not just parts of it).
Last edited by Scott; 03-06-2011 at 06:40 PM..
Reason: Added code tags
I have a shell script which gets passed a parameter which is a combination of Year and Julian Date <YYYYj>. So April 11th, julian date is 101. So if I wanted April 11th for 2003 I would get the following value 2003101. How would I convert that in unix to be 20030411? I am using the korn shell. (3 Replies)
Hi,
is there any possibility to find julian date for given corresping date.
I will be gladfull if i get it.
Requirement :
Input : 10 09 2006
output: julian date: 283
thanks
srikanth (2 Replies)
Hi,
I have script in unix which creates a julian date like 126 or 127
I want convert this julian date into calender date
ex : input 127
output 07/may/2007 or 07/05/2007 or 07/05/07
rgds
srikanth (6 Replies)
Hi,
Was using date +%Y%j to get current julian date. Can anyone let me know how can I get y'day's julin date. Thx
Did check FAQ but couldn't find anything.
Thanks. (3 Replies)
I'm trying to put together a little script that will move some files to a directory, uncompress the file then delete the file when processing is complete.
The files are all named using julian date
2009072.Z
2009071.Z
2009070.Z
2009069.Z
2009068.Z
2009067.Z
2009066.Z
2009065.Z... (8 Replies)
Hi,
im new for UNIX. i have a problem in date function. please help me to find a solution.
batchdate="29/10/2010"
nextdate="01/11/2010"
i want compare this two date. if my batch date greater than nextdate should prompt error message. how can i do that? as i know its better and safer if i... (2 Replies)
Hi all,
I require to convert julian date to normal calander date in unix
for eg julian date=122
now i want corresponding calander date
----------------------------------------
gr8 if give very small command/script
and please explain the steps as well(imp)
Thanks
... (3 Replies)
Need assistance . Below code gets me julian date . I wanted to add hour/24 to julian date and output it. Is there a way to do the calculation?
use Time::Local;
use POSIX qw(strftime);
my $time=timelocal(1,2,3,9,11,2013);
printf strftime "%j", localtime($time);
343 (3 Replies)
How to get Julian date (Three digit) of a given date (Not current date)? I do not have root privilege - so can not use date -d. Assume that we have three variables year, month and date.
Thx (5 Replies)
Discussion started by: Soham
5 Replies
LEARN ABOUT FREEBSD
jdate
CALENDAR(3) BSD Library Functions Manual CALENDAR(3)NAME
easterg, easterog, easteroj, gdate, jdate, ndaysg, ndaysj, week, weekday -- Calendar arithmetic for the Christian era
LIBRARY
Calendar Arithmetic Library (libcalendar, -lcalendar)
SYNOPSIS
#include <calendar.h>
struct date *
easterg(int year, struct date *dt);
struct date *
easterog(int year, struct date *dt);
struct date *
easteroj(int year, struct date *dt);
struct date *
gdate(int nd, struct date *dt);
struct date *
jdate(int nd, struct date *dt);
int
ndaysg(struct date *dt);
int
ndaysj(struct date *dt);
int
week(int nd, int *year);
int
weekday(int nd);
DESCRIPTION
These functions provide calendar arithmetic for a large range of years, starting at March 1st, year zero (i.e., 1 B.C.) and ending way beyond
year 100000.
Programs should be linked with -lcalendar.
The functions easterg(), easterog() and easteroj() store the date of Easter Sunday into the structure pointed at by dt and return a pointer
to this structure. The function easterg() assumes Gregorian Calendar (adopted by most western churches after 1582) and the functions
easterog() and easteroj() compute the date of Easter Sunday according to the orthodox rules (Western churches before 1582, Greek and Russian
Orthodox Church until today). The result returned by easterog() is the date in Gregorian Calendar, whereas easteroj() returns the date in
Julian Calendar.
The functions gdate(), jdate(), ndaysg() and ndaysj() provide conversions between the common "year, month, day" notation of a date and the
"number of days" representation, which is better suited for calculations. The days are numbered from March 1st year 1 B.C., starting with
zero, so the number of a day gives the number of days since March 1st, year 1 B.C. The conversions work for nonnegative day numbers only.
The gdate() and jdate() functions store the date corresponding to the day number nd into the structure pointed at by dt and return a pointer
to this structure.
The ndaysg() and ndaysj() functions return the day number of the date pointed at by dt.
The gdate() and ndaysg() functions assume Gregorian Calendar after October 4, 1582 and Julian Calendar before, whereas jdate() and ndaysj()
assume Julian Calendar throughout.
The two calendars differ by the definition of the leap year. The Julian Calendar says every year that is a multiple of four is a leap year.
The Gregorian Calendar excludes years that are multiples of 100 and not multiples of 400. This means the years 1700, 1800, 1900, 2100 are
not leap years and the year 2000 is a leap year. The new rules were inaugurated on October 4, 1582 by deleting ten days following this date.
Most catholic countries adopted the new calendar by the end of the 16th century, whereas others stayed with the Julian Calendar until the
20th century. The United Kingdom and their colonies switched on September 2, 1752. They already had to delete 11 days.
The function week() returns the number of the week which contains the day numbered nd. The argument *year is set with the year that contains
(the greater part of) the week. The weeks are numbered per year starting with week 1, which is the first week in a year that includes more
than three days of the year. Weeks start on Monday. This function is defined for Gregorian Calendar only.
The function weekday() returns the weekday (Mo = 0 .. Su = 6) of the day numbered nd.
The structure date is defined in <calendar.h>. It contains these fields:
int y; /* year (0000 - ????) */
int m; /* month (1 - 12) */
int d; /* day of month (1 - 31) */
The year zero is written as "1 B.C." by historians and "0" by astronomers and in this library.
SEE ALSO ncal(1), strftime(3)STANDARDS
The week number conforms to ISO 8601: 1988.
HISTORY
The calendar library first appeared in FreeBSD 3.0.
AUTHORS
This manual page and the library was written by Wolfgang Helbig <helbig@FreeBSD.org>.
BUGS
The library was coded with great care so there are no bugs left.
BSD November 29, 1997 BSD