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Full Discussion: Removing 0 from a specific position - if it exists
Top Forums Shell Programming and Scripting Removing 0 from a specific position - if it exists Post 302501451 by ctsgnb on Thursday 3rd of March 2011 02:26:36 PM
Old 03-03-2011
Code:
sed 's/^\(....\)0/\1/' input

could also be written
Code:
sed 's/^\(.\{4\}\)0/\1/' input

Code:
sed 's/^\(.\{13\}\)0/\1/' input

My advice : Take care : since you remove the 0 instead of replacing it with a <space> character you should FIRST remove the 0 that is the most on the RIGHT

Consider the following example :

Code:
Mar 03, 2011 10:38:35 AM

the 0 of the 10 is currently at the 15th position :

if you remove the 0 on fifth position, all character will be shifted to left so that the 0 of the 10 will be on the 14th position

Look the difference :
Code:
# echo "Mar 03, 2011 10:38:35 AM" | sed 's/^\(....\)0/\1/;s/^\(.\{13\}\)0/\1/'
Mar 3, 2011 1:38:35 AM

Code:
# echo "Mar 03, 2011 10:38:35 AM" | sed 's/^\(.\{13\}\)0/\1/;s/^\(....\)0/\1/'

Mar 3, 2011 10:38:35 AM

Another solution could be to replace the unexpected 0 with a space character, so the characters will keep their positions.
Last edited by ctsgnb; 03-03-2011 at 03:45 PM..
This User Gave Thanks to ctsgnb For This Post:
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