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Full Discussion: Shared Object Question
Top Forums Programming Shared Object Question Post 302501078 by Corona688 on Wednesday 2nd of March 2011 12:17:52 PM
Old 03-02-2011
Quote:
Originally Posted by dorik
Since I took unnecessary definitions outside of the library the library hasn't even been loading.
They would seem to be necessary, then. Remember that exporting dynamic symbols from your project exports your symbols, not the entire universe...

Also make sure your library isn't last in the link order, the stuff you want it to link to should come after it. I'm not sure that'll help, but sometimes that matters for static linking...
Quote:
If I can get it to load, I am hoping that static member won't be duplicated.
I don't think it works that way for the reasons I stated above.
Quote:
Edit: Just to make sure we're using the same terms: by definition I mean cpp and by declaration I mean header.
The compiler doesn't know any difference between header files and source files. What matters is what you put in them. So it's entirely possible for the wrong kind of declaration in a header file to create many conflicting symbols when included in several files.

I don't suppose you could reduce this to a minimal example?
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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