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Top Forums Shell Programming and Scripting Number of days between the current date and user defined date Post 302500679 by kshji on Tuesday 1st of March 2011 09:13:32 AM
Old 03-01-2011
Some days ago about same question.

You have variables YYYY DD MM, but try to use DD1, YYYY1, MM1.
And in function you have more than one echo. If you need test echo in function, then redirect it ex. to the stderr.
Code:
echo $year >&2

Now you echo your all values to the jd1 or jd2.

Read input version 2
Code:
echo 'Enter date in the format: dd mm yyyy'
read DD MM YYYY XSTR

No need to parse and so on.

Or
Code:
echo 'Enter date in the format: dd/mm/yyyy'
IFS="/" read DD MM YYYY XSTR
echo "$DD - $MM - $YYYY"

Or ...

Last edited by kshji; 03-01-2011 at 10:19 AM..
This User Gave Thanks to kshji For This Post:
 

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lchage(8)						      System Manager's Manual							 lchage(8)

NAME
lchage - Display or change user password policy SYNOPSIS
lchage [OPTION]... user DESCRIPTION
Displays or allows changing password policy of user. OPTIONS
-d, --date=days Set the date of last password change to days after Jan 1 1970. -E, --expire=days Set the account expiration date to days after Jan 1 1970. Set days to -1 to disable account expiration. -i, --interactive Ask all questions when connecting to the user database, even if default answers are set up in libuser configuration. -I, --inactive=days Disable the account after days after password expires (after the user user is required to change the password). -l, --list Only list current user's policy and make no changes. -m, --mindays=days Require at least days days between password changes. Set days to 0 to disable this checking. -M, --maxdays=days Require changing the password after days since last password change. Set days to 99999 to disable this checking. -W, --warndays=days Start warning the user days before password expires (before the user is required to change the password). EXIT STATUS
The exit status is 0 on success, nonzero on error. libuser Jan 12 2005 lchage(8)
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