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Top Forums Shell Programming and Scripting Number of days between the current date and user defined date Post 302500679 by kshji on Tuesday 1st of March 2011 09:13:32 AM
Old 03-01-2011
Some days ago about same question.

You have variables YYYY DD MM, but try to use DD1, YYYY1, MM1.
And in function you have more than one echo. If you need test echo in function, then redirect it ex. to the stderr.
Code:
echo $year >&2

Now you echo your all values to the jd1 or jd2.

Read input version 2
Code:
echo 'Enter date in the format: dd mm yyyy'
read DD MM YYYY XSTR

No need to parse and so on.

Or
Code:
echo 'Enter date in the format: dd/mm/yyyy'
IFS="/" read DD MM YYYY XSTR
echo "$DD - $MM - $YYYY"

Or ...

Last edited by kshji; 03-01-2011 at 10:19 AM..
This User Gave Thanks to kshji For This Post:
 

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DATEFMT_GET_PATTERN(3)							 1						    DATEFMT_GET_PATTERN(3)

IntlDateFormatter::getPattern - Get the pattern used for the IntlDateFormatter

	Object oriented style

SYNOPSIS
public string IntlDateFormatter::getPattern (void ) DESCRIPTION
Procedural style string datefmt_get_pattern (IntlDateFormatter $fmt) Get pattern used by the formatter. PARAMETERS
o $fmt - The formatter resource. RETURN VALUES
The pattern string being used to format/parse. EXAMPLES
Example #1 datefmt_get_pattern(3) example <?php $fmt = datefmt_create( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, 'MM/dd/yyyy' ); echo 'pattern of the formatter is : ' . datefmt_get_pattern($fmt); echo 'First Formatted output with pattern is ' . datefmt_format($fmt, 0); datefmt_set_pattern($fmt,'yyyymmdd hh:mm:ss z'); echo 'Now pattern of the formatter is : ' . datefmt_get_pattern($fmt); echo 'Second Formatted output with pattern is ' . datefmt_format($fmt, 0); ?> Example #2 OO example <?php $fmt = new IntlDateFormatter( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, 'MM/dd/yyyy' ); echo 'pattern of the formatter is : ' . $fmt->getPattern(); echo 'First Formatted output is ' . $fmt->format(0); $fmt->setPattern('yyyymmdd hh:mm:ss z'); echo 'Now pattern of the formatter is : ' . $fmt->getPattern(); echo 'Second Formatted output is ' . $fmt->format(0); ?> The above example will output: pattern of the formatter is : MM/dd/yyyy First Formatted output is 12/31/1969 Now pattern of the formatter is : yyyymmdd hh:mm:ss z Second Formatted output is 19690031 04:00:00 PST SEE ALSO
datefmt_set_pattern(3), datefmt_create(3). PHP Documentation Group DATEFMT_GET_PATTERN(3)
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