Sponsored Content
Top Forums UNIX for Advanced & Expert Users cut words based on the word count of a line Post 302500452 by vgersh99 on Monday 28th of February 2011 03:35:08 PM
Old 02-28-2011
Quote:
Originally Posted by COKEDUDE
I saw that from the link I gave. How do I cut the 4th word and 6th word based on word count.
This will return the last 'word' from the record/line.
Isn't that what your examples illustrate?

When you say 'cut words' what do you example mean?
Please provide a sample input a desired output.
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

cut last line of a word

Hi all, want to delete a crahecter from each line..? how can i do it... (2 Replies)
Discussion started by: bullz26
2 Replies

2. Shell Programming and Scripting

count no of words in a line

hi i have a string like str=abc def ghi jkl now i want to count the no of words in the string please help (7 Replies)
Discussion started by: satish@123
7 Replies

3. Shell Programming and Scripting

count no of words in a line

hi i have a line "abc,def,ghi,abc,def ,ghi,abc,def,ghi,abc,def ,ghi,abc,def,ghi,abc" I want to print the no of words, words separated by comma please help (3 Replies)
Discussion started by: Satyak
3 Replies

4. Shell Programming and Scripting

Count words on each line in file using xargs

Hi, im having a problem with xargs, i want to cout word of each line in file, and i HAVE to use xargs, i tried: cat file | xargs wc -w .....that uses all words in file like name of files and passed then to wc so it worte wc :somewordformfile is not i afile or directory cat file | xargs -I{} wc... (3 Replies)
Discussion started by: Qwetek
3 Replies

5. Shell Programming and Scripting

How to fetch rows based on line numbers or based on the beginning of a word?

I have a file which will have rows like shown below, ST*820*316054716 RMR*IV*11333331009*PO*40.31 REF*IV*22234441009*xsss471-2762 DTM*003*091016 ENT*000006 RMR*IV*2222234444*PO*239.91 REF*IV*1234445451009*LJhjlkhkj471-2762 </SPAN> DTM*003* 091016 RMR*IV*2223344441009*PO*40.31... (18 Replies)
Discussion started by: Muthuraj K
18 Replies

6. Shell Programming and Scripting

How to remove all words starting from a matching word in a line

Hi Guys, I have a file like this: wwwe 1 ioie ewew yyy uuu 88 erehrlk 4 ihoiwhe lkjhassad lkhsad yyy mmm 45 jhash lhasdhs lkhsdkjsn ouiyrshroi oihoihswodnw oiyhewe yyy ggg 77 I want to remove everything after "yyy" and including "yyy" from each line in the file. So I want:... (2 Replies)
Discussion started by: npatwardhan
2 Replies

7. Shell Programming and Scripting

How to remove all words from a matching word in a line?

Hi Guys, :p I have a file like this: 2010-04-25 00:00:30,095 INFO - ]- start process U100M4 2010-04-25 00:00:30,096 DEBUG - ] -- call EJB 2010-04-25 00:00:30,709 INFO - - end processU100M4 2010-04-25 00:00:30,710 DEBUG - got message=Sorry I want to out put format. 2010-04-25... (5 Replies)
Discussion started by: ooilinlove
5 Replies

8. Shell Programming and Scripting

Count and print all repeating words in a line

Gurus, I have a file containing lines like this : Now, number of words in each line varies. My need is, if a word repeats in a line get it printed. Also total number of repeats. So, the output would be : Any help would be highly appreciated. Thanks & Regards (5 Replies)
Discussion started by: AshwaniSharma09
5 Replies

9. UNIX for Advanced & Expert Users

Sort words based on word count on each line

Hi Folks :) I have a .txt file with thousands of words. I'm trying to sort the lines in order based on number of words per line. Example from: word word word word word word word word word word word word word word word word to desired output: word (2 Replies)
Discussion started by: martinsmith
2 Replies

10. Shell Programming and Scripting

Replace particular words in file based on if finds another words in that line

Hi All, I need one help to replace particular words in file based on if finds another words in that file . i.e. my self is peter@king. i am staying at north sydney. we all are peter@king. How to replace peter to sham if it finds @king in any line of that file. Please help me... (8 Replies)
Discussion started by: Rajib Podder
8 Replies
UDM_FIND(3)								 1							       UDM_FIND(3)

udm_find - Perform search

SYNOPSIS
resource udm_find (resource $agent, string $query) DESCRIPTION
Performs a search. The search itself. The first argument - session, the next one - query itself. To find something just type words you want to find and press SUBMIT button. For example, "mysql odbc". You should not use quotes " in query, they are written here only to divide a query from other text. mnoGoSearch will find all documents that contain word "mysql" and/or word "odbc". Best documents having bigger weights will be dis- played first. If you use search mode ALL, search will return documents that contain both (or more) words you entered. In case you use mode ANY, the search will return list of documents that contain any of the words you entered. If you want more advanced results you may use query language. You should select "bool" match mode in the search from. PARAMETERS
o $agent - A link to Agent, received after call to udm_alloc_agent(3). o $query - mnoGoSearch understands the following boolean operators: & - logical AND. For example, "mysql & odbc". mnoGoSearch will find any URLs that contain both "mysql" and "odbc". | - logical OR. For example "mysql|odbc". mnoGoSearch will find any URLs, that contain word "mysql" or word "odbc". ~ - logical NOT. For example "mysql & ~odbc". mnoGoSearch will find URLs that contain word "mysql" and do not contain word "odbc" at the same time. Note that ~ just excludes given word from results. Query "~odbc" will find nothing! () - group command to compose more complex queries. For example "(mysql | msql) & ~postgres". Query language is simple and powerful at the same time. Just consider query as usual boolean expression. RETURN VALUES
Returns a result link identifier on success or FALSE on failure. PHP Documentation Group UDM_FIND(3)
All times are GMT -4. The time now is 04:07 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy