i want to convert from an integer to a string..in unix...i am writing a C program with embedded SQL...
I remeber using itoa...but for some reason it doesnt work......i cant find it in the manual.....
Maybe that is the wrong command.....
but i have checked Dev Studio.....and it doest exist in the... (6 Replies)
I'm new at scripting but I thought I was getting pretty good at it. I've hit a snag. I try to use expr to compute a fraction say: expr 3 / 4, and I'm getting zero. I guess it's just truncating to the integer, in this case 0, but I need the decimal 0.75. What can I do to compute this value in... (2 Replies)
Hi fellows!!
i'm doing something which is not working out for me properly which i don't understand why
nowdate=`date +%s`
echo $nowdate
now the problem how to convert a date which is stored in a variable
mydate="22/Oct/2011"
mydate=`date -d '$mydate' +%s`
it gives error... (11 Replies)
Hi All,
I want to convert string in format YYYYMMDD(20120607) to date in unix and add 1 day to it and convert back to string in format YYYYMMDD. Please help. (4 Replies)
Hi All,
sessionid_remote=$(echo "select odb_sessionid from sysopendb where odb_dbname='syscdr';" | sudo -u cucluster ssh ucbu-aricent-vm93 "source /opt/cisco/connection/lib/connection.profile; $INFORMIXDIR/bin/dbaccess sysmaster@ciscounity")
for sid in $sessionid_remote;do
if * ]];... (2 Replies)
Hi all,
I am trying to write a script to be able to
Run top command
Pick the PIDs that are taking more than 90% of CPU time
Get more details like what is the script name and location for that PID
Script should run until I manually kill it by ctrl + C
I have come up with following script... (3 Replies)
i have some set of date data inside csv files and need to convert the timezone,
08302016113611861
08302016113623442
08302016113541570
08302016113557732
08302016113548439
08302016112853115
08302016113620684
08302016113432827
08302016113630321
date format is : %m%d%Y%H%M%Smilisec
... (2 Replies)
Hi,
I have a requirement where I am getting date in string format (20161130). I need to add 20 days(not no. 20) to the above string. The o/p should 20161220.
In case of 20170228, it should show 20170320.
Could you please help me with the command to achieve this.
Note: I am using AIX 7.1... (5 Replies)
I have data as below
"ROWS merge process complete. thousand rows changed"
I need to get a variable assigned the value of 1000. I mean convert the string thousand to 1000.
Any help or pointer.
Please use CODE tags as required by forum rules! (6 Replies)
Discussion started by: dsravanam
6 Replies
LEARN ABOUT PHP
gmmktime
GMMKTIME(3) 1 GMMKTIME(3)gmmktime - Get Unix timestamp for a GMT dateSYNOPSIS
int gmmktime ([int $hour = gmdate("H")], [int $minute = gmdate("i")], [int $second = gmdate("s")], [int $month = gmdate("n")], [int
$day = gmdate("j")], [int $year = gmdate("Y")], [int $is_dst = -1])
DESCRIPTION
Identical to mktime(3) except the passed parameters represents a GMT date. gmmktime(3) internally uses mktime(3) so only times valid in
derived local time can be used.
Like mktime(3), arguments may be left out in order from right to left, with any omitted arguments being set to the current corresponding
GMT value.
PARAMETERS
o $hour
- The number of the hour relative to the start of the day determined by $month, $day and $year. Negative values reference the hour
before midnight of the day in question. Values greater than 23 reference the appropriate hour in the following day(s).
o $minute
- The number of the minute relative to the start of the $hour. Negative values reference the minute in the previous hour. Values
greater than 59 reference the appropriate minute in the following hour(s).
o $second
- The number of seconds relative to the start of the $minute. Negative values reference the second in the previous minute. Values
greater than 59 reference the appropriate second in the following minute(s).
o $month
- The number of the month relative to the end of the previous year. Values 1 to 12 reference the normal calendar months of the
year in question. Values less than 1 (including negative values) reference the months in the previous year in reverse order, so 0
is December, -1 is November, etc. Values greater than 12 reference the appropriate month in the following year(s).
o $day
- The number of the day relative to the end of the previous month. Values 1 to 28, 29, 30 or 31 (depending upon the month) refer-
ence the normal days in the relevant month. Values less than 1 (including negative values) reference the days in the previous
month, so 0 is the last day of the previous month, -1 is the day before that, etc. Values greater than the number of days in the
relevant month reference the appropriate day in the following month(s).
o $year
- The year
o $is_dst
- Parameters always represent a GMT date so $is_dst doesn't influence the result.
Note
This parameter has been removed in PHP 7.0.0.
RETURN VALUES
Returns a integer Unix timestamp.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 7.0.0 | |
| | |
| | $is_dst parameter has been removed. |
| | |
| 5.1.0 | |
| | |
| | As of PHP 5.1.0, the $is_dst parameter became |
| | deprecated. As a result, the new timezone han- |
| | dling features should be used instead. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
gmmktime(3) basic example
<?php
// Prints: July 1, 2000 is on a Saturday
echo "July 1, 2000 is on a " . date("l", gmmktime(0, 0, 0, 7, 1, 2000));
?>
SEE ALSO mktime(3), date(3), time(3).
PHP Documentation Group GMMKTIME(3)