I know if i use grep -n that the output will have the lines numbered but is there a way to grep the actually line number.
so like this
grep -n "one" /usr/dict/numbers
1:one
21:twenty-one
31:thirty-one
41:forty-one
51:fifty-one
61:sixty-one
71:seventy-one
81:eighty-one
91:ninety-one
... (1 Reply)
Hi Folks,
I am searching for a pattern in logs through putty by opening the file in vi editor
and reaching to the last of the file by $ and then searching the pattern , lets say I have to search the pattern abc then it would be ?abc Now I want line numbers along with the matching pattern to be... (3 Replies)
Hi,
I have got the below requirement. please suggest.
I have a file like,
Processing Item is:
/data/ing/cfg2/abc.txt
/data/ing/cfg3/bgc.txt
Processing Item is:
/data/cmd/for2/ght.txt
/data/kernal/config.klgt.txt
I want to process the above file to get the output file like,
... (5 Replies)
I'm trying to grep lines where the digits at the end of each line are greater than digits. Tried this but it will only allow me to specify 2 digits. Any ideas would greatly be appreciated. grep -i '\<\{3,4,5\}\>' file
---------- Post updated at 05:58 PM ---------- Previous update was at 05:41... (1 Reply)
here is what i want to achieve.. i have a file with below contents
cat fileName
blah blah blah
.
.DROP this
REJECT that
.
--sport 7800 -j REJECT --reject-with icmp-port-unreachable
--dport 7800 -j REJECT --reject-with icmp-port-unreachable
.
.
.
more blah blah blah
--dport 3306... (14 Replies)
Hai,
I want to select only line numbers into a file if some pattern matches. I have written my script like below but its not working.
#!/bin/sh
file='/home/testfile1'
filesearch='/home/test00'
while read line
do
search=`echo $line |cut -c 1-24`
echo $search
echo `grep -n ""... (3 Replies)
We are using Red Hat Linux.
I have a flat file with among other things, the following lines, which appear occasionally throughout the file:
Using sed, I delete this line:
L;L;L;L;R;R;R;L;R;L;R;R;R;L;L;L
With:
/^;;;;;*/d
Works fine every time.
However, I cannot delete... (6 Replies)
Hi ,
I have a file where i have modifed certain things compared to original file . The difference of the original file and modified file is as follows.
# diff mir_lex.c.modified mir_lex.c.orig
3209c3209
< if(yy_current_buffer -> yy_is_our_buffer == 0) {
---
>... (5 Replies)
How would you grep for a line containing only 5 numbers? Something like this.
10 2 12 1 13 (4 Replies)
Discussion started by: cokedude
4 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)